Finite Metric Space Imbedding in Manifolds

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Discussion Overview

The discussion centers on the question of whether every finite metric space can be embedded in a manifold. Participants explore the implications of this question, particularly focusing on specific cases such as metric spaces with four points and the characteristics of the manifolds involved.

Discussion Character

  • Exploratory, Debate/contested, Conceptual clarification

Main Points Raised

  • One participant questions if every finite metric space is imbeddable in a manifold, seeking a general answer for all finite metric spaces.
  • Another participant suggests starting with the specific case of embedding metric spaces with four points into Riemannian manifolds, proposing a stepwise approach from smaller sets.
  • A different participant presents a specific configuration of a four-point metric space and expresses uncertainty about its embeddability in a manifold, noting a lack of conclusive proof.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the general question of embeddability. There are competing views on how to approach the problem, particularly regarding specific cases and the types of manifolds considered.

Contextual Notes

The discussion does not resolve the mathematical steps necessary to prove or disprove the embeddability of certain finite metric spaces, and it is unclear what assumptions are being made about the types of manifolds involved.

Dragonfall
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Is every finite metric space imbeddable in a manifold?

That is, for every finite metric space (X,d), does there exist some manifold such that there are |X| many points on it which is isometric (with the length of geodesics as metric) to (X,d)?
 
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Can you do a set with 4 points?
 
What do you mean?
 
"Every finite metric space" is a tall order. Try starting with embedding "every metric space with 4 points" into Riemannian manifolds. (Actually, why not start with 0, 1, 2, 3, and then 4?)

(P.S. I assume you mean "connected and Riemannian" manifolds?)
 
OK, it seems this one

o
\
o ---- o
/
o

where the metric is the number of steps between nodes, can't be done. But I can't prove it conclusively.
 

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