First and Second Order Differential Equation

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SUMMARY

The discussion focuses on solving first and second order differential equations, specifically demonstrating that phi(t) = e^2t is a solution to the equation y' - 2y = 0, and that phi(t) = 1/t is a solution to y' + y^2 = 0 for t > 0. It is established that C*phi(t) is a solution for any constant C in the first case, while in the second case, y = c*phi(t) is only a solution if c = 0 or c = 1. Participants clarify that "show" means to substitute the solutions into the original equations to verify their validity.

PREREQUISITES
  • Understanding of first and second order differential equations
  • Familiarity with the method of substitution in differential equations
  • Knowledge of exponential functions and their properties
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the method of solving first order linear differential equations
  • Learn about the existence and uniqueness theorem for differential equations
  • Explore the concept of integrating factors in differential equations
  • Investigate the implications of initial conditions on solutions of differential equations
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Students studying calculus, mathematics educators, and anyone seeking to deepen their understanding of differential equations and their applications in various fields.

aznkid310
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Homework Statement



a) Show that phi(t) = e^2t is a solution of y' - 2y = 0 and that C*phi(t) is also a solution for any constant C

b) Show that phi(t) = 1/t is a solution of y' + y^2 = 0 for t>0 but that y = c*phi(t) is not a solution unless c = 0 or c = 1

Homework Equations



What do they mean by "show'?

The Attempt at a Solution



a) dy/2y = dt

(1/2)ln(y) = t + C

y = e^(2t + c) = Ce^2t, where c is any constant

Now what?

b) -dy/y^2 = dt

1/y = t + C

y = 1/(t + C)

Again, how do i show?
 
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Hi aznkid310! :smile:
aznkid310 said:
a) dy/2y = dt

(1/2)ln(y) = t + C

y = e^(2t + c) = Ce^2t, where c is any constant

Now what?

That's it! You've done it! :smile:

b) -dy/y^2 = dt

1/y = t + C

y = 1/(t + C)

Again, how do i show?

Again, that's it … except of course you still have to make the obvious remark that C/t is not a solution! :smile:
What do they mean by "show'?

I think they just mean "prove". :smile:

Alternatively, they may mean "no need to pretend you don't know the answer … just plug the answer straight into the original equation and confirm that it works" :rolleyes:

Better ask your teacher/tutor/professor which one it is! :smile:
 
'Show' just means substitute the given solutions into the differential equations and verify that they work or not. You don't have to solve the differential equation.
 

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