First derivative: chain rule: easy for you guys

In summary, the conversation discusses the first derivative and the chain rule, specifically in relation to the function Y=E^(-mx). The participants also touch on the derivative of a constant times a function and the product rule. The solution is determined to be Y'=0, with G'(x) being equal to -m.
  • #1
physicsed
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0
[SOLVED] first derivative: chain rule: easy for you guys

Y=E^(-mx)
f= E^x g= -mx
f'= E^x g'= o





E^(-mx) * 0(E^(-mx))
i think, not sure though



Y'= 0
which is wrong
someone help
 
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  • #2
[tex]f(x)=e^{g(x)}[/tex]

[tex]f'(x)=e^{g(x)}g'(x)[/tex]

[tex]y=e^{-mx}[/tex]

[tex]y'=-me^{-mx}[/tex]
 
Last edited:
  • #3
yes!
 
  • #4
the derivative of e is itself ... times the derivative of it's exponent.
 
  • #5
how did you get g'(x)
i thought the (m) was constant thus making the the derivative equal to 0
 
  • #6
Do this one for me ...

[tex]y=ax[/tex]

What is it's derivative?
 
  • #7
gosh!
well i would use the product rule or maybe not.
f= x g=ax
f'= 1 g'=product rule
high school calc.
 
  • #8
Don't worry about the product rule when you're differentiating with a constant.

The derivative of a constant times a function is simply ...

[tex]\frac{d}{dx}=cf'(x)[/tex]

[tex]y=ax[/tex]

[tex]y'=a[/tex] by constant rule

[tex]y'=a+x\cdot0=a[/tex] by product rule

Do you see why we don't need the product rule?
 
  • #9
[tex]ysingle-quote=a+x\cdot0=a[/tex]
times 0 would be zero,right?
 
  • #10
never mind, sorry.
 
  • #11
lets just go back to the original equation
[tex]fsingle-quote(x)=e^{g(x)}gsingle-quote(x)[/tex]
what is g'(X) equall to
 
  • #12
read my previous posts!
 
  • #13
g'= -m
Solved.
thanks for the help
 
  • #14
:) anytime
 

1. What is the first derivative?

The first derivative represents the rate of change of a function at a given point. It measures how much a function's output changes with respect to its input.

2. How is the first derivative calculated?

The first derivative is calculated using the derivative formula, which involves taking the limit of a function as its input approaches a specific value. This is also known as the difference quotient.

3. What is the chain rule in the context of the first derivative?

The chain rule is a method for finding the derivative of a composite function, which is a function that is composed of two or more other functions. It allows us to break down the derivative of a composite function into smaller, more manageable parts.

4. Why is the chain rule important?

The chain rule is important because it allows us to find the derivative of complicated functions by breaking them down into simpler parts. It is a fundamental tool in calculus and is used in many real-world applications, such as in physics, engineering, and economics.

5. Can you provide an example of using the chain rule to find the first derivative?

Sure, let's say we have the function f(x) = (x^2 + 1)^3. Using the chain rule, we can break this down into two simpler functions: g(x) = x^2 + 1 and h(x) = x^3. Then, the derivative of f(x) can be found by multiplying the derivative of g(x) (2x) with the derivative of h(x) (3x^2), resulting in f'(x) = 6x(x^2 + 1)^2.

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