Partial derivative chain rule proof

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SUMMARY

The discussion focuses on proving the equation d²u/dx² + d²u/dy² = e⁻²s[d²u/ds² + d²u/dt²] for the function u = f(x, y) where x = e^s cos(t) and y = e^s sin(t). Participants express confusion regarding the interpretation of the operator d/ds, clarifying that it is not simply the second partial derivative of s. The conversation highlights the need for a clearer understanding of the transformation from Cartesian to polar coordinates and the resulting terms in the equation.

PREREQUISITES
  • Understanding of partial derivatives and their notation
  • Familiarity with the chain rule in multivariable calculus
  • Knowledge of transformations between Cartesian and polar coordinates
  • Basic proficiency in calculus, specifically second derivatives
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Learn about transformations between Cartesian and polar coordinates
  • Review the properties and applications of second partial derivatives
  • Explore examples of deriving equations involving multiple variables
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Students and educators in calculus, particularly those focusing on multivariable calculus and differential equations, as well as anyone seeking to deepen their understanding of the chain rule and partial derivatives.

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Homework Statement



If u=f(x,y) where x=escost and y=essint

show that d2u/dx2+d2u/dy2 = e-2s[d2u/ds2+d2u/dt2

Homework Equations



http://s11.postimage.org/sjwt1wkvl/Untitled.jpg

The Attempt at a Solution



ok i don't understand how they got to that


i don't know what d/ds is supposed to do exactly, i thought it was the second partial derivative of s, but it seems that it's not if we check the answer.


i basically got e^s cost (d^2/dx^2) + e^s sint (d^2u/dy^2), but they got 6 terms. i am kinda lost, can you explain to me what d/ds is supposed to do?
 
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Maybe you should try typing the problem a little clearer. I think I could help you with this.
 

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