First-Derivative Test: Finding Absolute Extrema (x=-8.8 and x=-7.2)

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Homework Help Overview

The discussion revolves around the application of the first-derivative test to find absolute extrema of a function, specifically at the points x = -8.8 and x = -7.2. Participants are analyzing the behavior of the derivative g'(x) and its implications for identifying maximum and minimum values.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to determine whether the points x = -8.8 and x = -7.2 represent absolute or relative extrema. There is discussion about the sign changes of g'(x) and how they relate to local and absolute maxima or minima. Some participants express confusion regarding the definitions of relative versus absolute extrema.

Discussion Status

There is an ongoing exploration of the implications of the derivative's sign changes and the presence of a vertical asymptote at x = -8. Some participants have offered insights into the behavior of g'(x) around the critical points, while others are clarifying their understanding of the terminology used in the context of extrema.

Contextual Notes

Participants are working with a specific function and its derivative, with a focus on critical points and the effects of asymptotes. There is an acknowledgment of potential misunderstandings regarding the signs of the derivative in different intervals.

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Homework Statement


http://img5.imageshack.us/img5/2218/49718059.jpg


Homework Equations


in picture


The Attempt at a Solution


why am i getting this wrong?
when x=-8.8 its the abs.max value
and x=-7.2 is the abs.min value...
 
Last edited by a moderator:
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-8.8 appears to be a relative min if g'(x) changes from - to +.

Think about it down and then up: \ /

seems like a minimum
 
MathDude said:
-8.8 appears to be a relative min if g'(x) changes from - to +.

Think about it down and then up: \ /

seems like a minimum

im a bit confused with the wording.
relative = local or absolute?
i assumed it is absolute.

so i kinda get why -8.8 is min.. but then -7.2 has to be max, which would look like: /
is that correct?
 
I had a great right up for you, but when I posted it I was timed out and had to login in (drives me nuts!) and lost everything. I don't have time to write it again, but here is a short version.

g'(x) is

+ (-inf, -8.8)
- (-8.8, -8)
- (-8, -7.2) Asymptote at -8
+ (-7.2, + inf)

I didn't observe the vertical asymptote at -8 in my earlier post. This changes the slope.

-8.8 is actually a max

-7.2 is a min.

Relative implies either local or abs. Evaluating g(x) at the critical points will enable you to tell if its local or abs. Abs values will yields the very largest and very smallest values for g(x) for all values of x within the given domain. Locals give you min or max within a local range. Locals can be absolute if there is only one max and/or one min. Say you have two rel max, the point with a larger g(x) will be the abs and the smaller g(x) will be the local.
 
MathDude said:
I had a great right up for you, but when I posted it I was timed out and had to login in (drives me nuts!) and lost everything. I don't have time to write it again, but here is a short version.

g'(x) is

+ (-inf, -8.8)
- (-8.8, -8)
- (-8, -7.2) Asymptote at -8
+ (-7.2, + inf)

I didn't observe the vertical asymptote at -8 in my earlier post. This changes the slope.

-8.8 is actually a max

-7.2 is a min.

Relative implies either local or abs. Evaluating g(x) at the critical points will enable you to tell if its local or abs. Abs values will yields the very largest and very smallest values for g(x) for all values of x within the given domain. Locals give you min or max within a local range. Locals can be absolute if there is only one max and/or one min. Say you have two rel max, the point with a larger g(x) will be the abs and the smaller g(x) will be the local.


so would that work:
http://img29.imageshack.us/img29/5402/40917982.jpg

the only thing i don't get is why
- (-8.8, -8)
- (-8, -7.2)
and not +?
 
Last edited by a moderator:
g'(x) can change signs only at zeros in the numerator, which are x = -8.8 and x = -7.2. For x < -8.8, g'(x) > 0. For x > -7.2, g'(x) > 0. For -8.8 < x < -7.2, g'(x) < 0 (although g'(x) is undefined at x = -8.)
 
Mark44 said:
g'(x) can change signs only at zeros in the numerator, which are x = -8.8 and x = -7.2. For x < -8.8, g'(x) > 0. For x > -7.2, g'(x) > 0. For -8.8 < x < -7.2, g'(x) < 0 (although g'(x) is undefined at x = -8.)

i got it! the problem was with the + and - signs.. i had to switch places! what a stupid mistake :S
 
Last edited:

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