First Order Circuit: Replacing Inductor & Current Source

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SUMMARY

The discussion focuses on the behavior of a first-order circuit when an inductor is replaced with a short circuit and the implications for a current source. It is established that the voltage across the inductor becomes zero, allowing current to flow through a 3k resistor while the current source continues to draw 5mA regardless of the voltage across it. The removal of the 2k and 6k resistors is confirmed, as their voltage is also zero, resulting in no current flow through them. The steady current through the inductor is clarified to be 2mA.

PREREQUISITES
  • Understanding of first-order circuits
  • Knowledge of Kirchhoff's Current Law (KCL)
  • Familiarity with Ohm's Law
  • Basic concepts of current sources and inductors
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  • Study the effects of replacing inductors in RLC circuits
  • Learn about the behavior of ideal current sources in circuit analysis
  • Explore the implications of KCL in complex circuits
  • Investigate transient response in first-order circuits
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Electrical engineering students, circuit designers, and anyone involved in analyzing first-order circuits and current source behavior.

Jebus_Chris
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I'm not sure what happens when you replace the inductor with a short circuit. The current source is what throws me off.

One thought I had was that you can remove the 6 and 2 kohm resistors, but then I don't know what ahppens to the current source.
http://imgur.com/lks7y
Thanks
 
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Everything you've said is right. The voltage across the inductor being 0 also means some current is flowing through the 3k resistor. The current source demands a certain current flow, so KCL should give you the inductor's steady current.
 
So then are you saying that you remove the current source as well since the voltage around it is zero?
 
Jebus_Chris said:
So then are you saying that you remove the current source as well since the voltage around it is zero?

The question is designed to trick your intuition. A current source can pull any amount of current no matter what the voltage across it is, including 0 volts.

What you've said about the 2k and 6k resistors is correct -- the voltage across them is zero so Ohm's law gives zero current through them. The current source continues to draw 5mA no matter what.
 
Last edited:
Ok, so then you're saying that there is 2mA of current traveling up [i(0) = -2] through the inductor?
 
Yes, that's it.
 

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