1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

First Order Differential Equation

  1. Oct 21, 2009 #1
    1. The problem statement, all variables and given/known data
    Solve the following first order differential equation for x,

    [tex]\frac{dy}{dx}[/tex] = 3xy + xy2

    2. Relevant equations
    Methods: Separation of Variables, Define an Integrating Factor



    3. The attempt at a solution
    I have been staring at this question for a while now, hoping that somehow the numbers would start looking nicer for me to solve, but alas this has not happened. I am totally stumped here, any help to steer me in the right direction would be greatly appreciated.
     
  2. jcsd
  3. Oct 21, 2009 #2
    Start by seperating the left and right hand side, such that on one side you only have a y-dependence and on the other only an x-dependence. In other words, you want something like this:

    [tex] f(y)dy = g(x) dx[/tex]

    Written this way it's possible to integrate both sides (do you see why?). You can post your answer or attempt here.
     
  4. Oct 21, 2009 #3

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    That's separable: dy/dx= x(3y+ y2).
     
  5. Oct 21, 2009 #4
    Thanks for the quick reply, so,

    [tex]\frac{dy}{dx}[/tex] = x(3y + y2)

    [tex]\frac{1}{3y + y^2}[/tex]dy = x dx

    However, integrating the left hand side is beyond the scope of the subject I am taking at the moment. That's why they have asked to solve for x, I think. Is it still possible to solve for x using this method?
     
  6. Oct 21, 2009 #5
    Any ideas?
     
  7. Oct 21, 2009 #6
    Are you sure about that? I don't really see an easier approach then to solve these integrals.

    The integral on the left hand side is probably not 'out of your scope'. The trick is to seperate the fraction. It goes like this:

    You have:
    [tex]\frac{1}{3y+y^2} = \frac{1}{y(3+y)}[/tex]
    Now make the following 'guess':
    [tex]\frac{1}{y(3+y)} = \frac{a}{y}+\frac{b}{3+y}[/tex]
    That is, we have split the fraction into two easier fractions. We just need to determine a and b -- I'll leave this up to you.

    Answer:
    [tex]\frac{1}{3y+y^2} = \frac{1/3}{y}-\frac{1/3}{3+y}[/tex]
    You should be able to solve the integrals using this form.
     
  8. Oct 21, 2009 #7

    Mark44

    Staff: Mentor

    If all you need to do is solve for x without solving the differential equation, you can do that in one step, starting with the 2nd equation above.
     
  9. Oct 21, 2009 #8
    Ah OK, so you use the partial fraction method then integrate each term. Cheers xepma, I should be able to do it now. Also thanks for the input everyone.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: First Order Differential Equation
Loading...