First order differential equation

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Homework Help Overview

The discussion revolves around solving a first-order differential equation given by the expression 1+(x-x^2*e^(2y))(dy/dx) = 0. Participants are exploring various approaches to tackle this equation, including algebraic manipulation and substitution methods.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants attempt to rearrange the equation for separation of variables, while others express uncertainty about the approach due to the presence of x^2 in the equation. There are discussions about the effectiveness of different substitutions, such as letting z = e^(2y) versus z = x^2*e^(2y).

Discussion Status

The discussion is ongoing, with participants sharing their thoughts on the separability of the equation and questioning the assumptions made in the initial attempts. Some guidance has been offered regarding potential substitutions, but there is no clear consensus on the best approach yet.

Contextual Notes

Participants note that the problem is labeled as "very tricky," which may influence their interpretations and approaches. There is also mention of homework constraints that prevent providing complete solutions.

Romaha_1
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Homework Statement



Solve the differential equation:

Homework Equations



1+(x-x^2*e^(2y))(dy/dx) = 0

The Attempt at a Solution



No idea how to approach this.
 
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Romaha_1 said:

Homework Statement



Solve the differential equation:

Homework Equations



1+(x-x^2*e^(2y))(dy/dx) = 0

The Attempt at a Solution



No idea how to approach this.
It looks pretty clear to me. Basic algebra gives
x(1- e^{2y})dy/dx= -1
and then separate variables as
(1- e^{2y})dy= -\frac{1}{x}dx

Now integrate.
 
HallsofIvy said:
It looks pretty clear to me. Basic algebra gives
x(1- e^{2y})dy/dx= -1
and then separate variables as
(1- e^{2y})dy= -\frac{1}{x}dx

Now integrate.

Hmm, there's an x^2 in the equation, I think you missed that bit.
 
Hi Romaha_1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Does putting z = e2y help? :smile:
 
tiny-tim said:
Hi Romaha_1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Does putting z = e2y help? :smile:


No it doesn't, does it?
 
JFonseka said:
Hmm, there's an x^2 in the equation, I think you missed that bit.

Yes, that's the reason I don't know how to do it. I don't think it is a mistake in the problem, since there is a sign "(very tricky)" after it on the problem set.
 
Altabeh said:
No it doesn't, does it?

Doesn't it? :smile:
 
Romaha_1 said:
Yes, that's the reason I don't know how to do it. I don't think it is a mistake in the problem, since there is a sign "(very tricky)" after it on the problem set.

The question isn't necessarily wrong, I'm not too good at this stuff at all. It just seemed to me that HallsofIvy was attempting the separable ODE approach, but missed the x^2.

I think it should be:

(e^2y)*dy = ((-1-x)/(-x^2))*dx

(e^{2y})*dy = (\frac{1-x}{-x^{2}})*dx

after the separation.

Now you must integrate it. I'm not too sure if I'm right, so be careful.
 
Last edited:
JFonseka said:
The question isn't necessarily wrong, I'm not too good at this stuff at all. It just seemed to me that HallsofIvy was attempting the separable ODE approach, but missed the x^2.

Yeah, I understand what you meant and agree with you that the separable approach does not work; it was my assumption that the question was wrong.
 
  • #10
Romaha_1 said:
Yeah, I understand what you meant and agree with you that the separable approach does not work; it was my assumption that the question was wrong.

I never said the Separable ODE approach doesn't work.
 
  • #11
JFonseka said:
I never said the Separable ODE approach doesn't work.

Sorry, for some reason I could not see the end of your previous post. But still, I do not understnad how this works because the whole expression (x-x2*e2y) is multiplied by dy/dx, not just x2*e2y.
 
  • #12
tiny-tim said:
Hi Romaha_1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Does putting z = e2y help? :smile:


Hi tiny-tim, thank you for the idea!

But I could solve it only when letting z = x2*e2y; I still do not see how this is possible with z = e2y.
 
  • #13
Romaha_1 said:
No idea how to approach this.
tiny-tim said:
Does putting z = e2y help? :smile:
Romaha_1 said:
Hi tiny-tim, thank you for the idea!

But I could solve it only when letting z = x2*e2y; I still do not see how this is possible with z = e2y.

ah … on this forum, we don't give you the full answer …

so, since you had no idea, I sort-of pushed you half-way (-1 = (x - x2z)(1/2z)dz/dx), and left you to finish it. :wink:

having said that, I don't see how z = x2*e2y does it … perhaps I'm misreading the question? :redface:
 

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