First time poster needs help with a problem at wits end

[Finns14]

After leaving the end of a ski ramp, a ski jumper lands downhill at a point that is displaced 51.8 m horizontally from the end of the ramp. His velocity, just before landing, is 20.7 m/s and points in a direction 43.3 degrees below the horizontal. Neglecting air resistance and any lift that he experiences while airborne, find (a) the magnitude and (b) the direction of his initial velocity when he left the end of the ramp.

That is the problem I understand mostly how to do this problem but this is only after hours of struggling with it. I am getting frustrated that the simple math and assiging negative and positive vaule are making me unable to solve the problem.

 

[member 553083]

a) The magnitude of his initial velocity when he left the end of the ramp can be found using the Pythagorean theorem. The horizontal and vertical components of the velocity are given, so the magnitude can be found as:V = √(20.7^2 + 51.8^2) = 52.1 m/sb) The direction of the initial velocity can be found using trigonometry. The angle below the horizontal is given, so the angle above the horizontal (which is the direction of the initial velocity) can be found as:θ = 90° - 43.3° = 46.7°