# Kinematics: Final velocity components

## Homework Statement

A skier leaves the ramp of a ski jump with a velocity of 10.9 m/s, 13.9° above the horizontal. The slope is inclined at 48.4°, and air resistance is negligible. Calculate the velocity components just before the landing. Enter the x-component (horizontal) first and then the y-component (vertical).

d=vit + 0.5at^2
vf=vi +at

## The Attempt at a Solution

This is a second part of the question. So previously i found the total time the skier was in the air which was 2.965 seconds. I took his initial velocity and did Vsintheta to find verical velocity, and Vcostheta to find the horizontal velocity. Then i found the time where the skier reached his max height by using vf=vi +at and multiplied this time by 2.

Then i subtracted this time by the total time to see the time that he will accelerate down. I added the vertical velocity with the acceleration times the time accelerating to find the final velocity. But in the end it was wrong. What did i do wrong?

## Answers and Replies

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The slope is inclined at 48.4°
Do you mean that the slope is declined at 48.4[itex]^\circ[/tex] (or that the slope falls at an angle of 48.4[itex]^\circ[/tex] below horizontal)?

Or, is the skier truly jumping onto an uphill slope?

Heres a picture of it:

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Do you mean that the slope is declined at 48.4[itex]^\circ[/tex] (or that the slope falls at an angle of 48.4[itex]^\circ[/tex] below horizontal)?

Or, is the skier truly jumping onto an uphill slope?
Here is a picture of it: