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Kinematics: Final velocity components

  • Thread starter huynhtn2
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  • #1
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Homework Statement


A skier leaves the ramp of a ski jump with a velocity of 10.9 m/s, 13.9° above the horizontal. The slope is inclined at 48.4°, and air resistance is negligible. Calculate the velocity components just before the landing. Enter the x-component (horizontal) first and then the y-component (vertical).


Homework Equations



d=vit + 0.5at^2
vf=vi +at
vf^2=Vi^2 +ad

The Attempt at a Solution



This is a second part of the question. So previously i found the total time the skier was in the air which was 2.965 seconds. I took his initial velocity and did Vsintheta to find verical velocity, and Vcostheta to find the horizontal velocity. Then i found the time where the skier reached his max height by using vf=vi +at and multiplied this time by 2.

Then i subtracted this time by the total time to see the time that he will accelerate down. I added the vertical velocity with the acceleration times the time accelerating to find the final velocity. But in the end it was wrong. What did i do wrong?
 

Answers and Replies

  • #2
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The slope is inclined at 48.4°
Do you mean that the slope is declined at 48.4[itex]^\circ[/tex] (or that the slope falls at an angle of 48.4[itex]^\circ[/tex] below horizontal)?

Or, is the skier truly jumping onto an uphill slope?
 
  • #3
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Heres a picture of it:
 

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  • #4
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Do you mean that the slope is declined at 48.4[itex]^\circ[/tex] (or that the slope falls at an angle of 48.4[itex]^\circ[/tex] below horizontal)?

Or, is the skier truly jumping onto an uphill slope?
Here is a picture of it:
 

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