Fixing an Incorrect Equation Answer

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Homework Help Overview

The discussion revolves around the gravitational potential energy (GPE) equation, particularly in the context of calculating the change in GPE when moving from the Earth's surface to a point 424 km above it. Participants are exploring the implications of using different expressions for GPE and the significance of reference points in these calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the exact GPE expression versus an approximation, questioning the validity of results obtained from both methods. There are inquiries about the correctness of specific numerical answers and the importance of showing work in calculations.

Discussion Status

Some participants have provided guidance on how to approach the problem, suggesting the need to calculate the change in GPE using both the exact formula and an approximation for verification. There is an ongoing exploration of the implications of different methods and the need for clarity in calculations.

Contextual Notes

Participants are considering the reference point for GPE and the significance of using the correct formula for a change in height. There are mentions of homework constraints regarding significant figures and the requirement to show calculations.

highschoolphysics
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Homework Statement
How much gravitational potential energy is required to lift a 9270-kg Progress spacecraft to the altitude of the International Space Station, 424 km above the surface of the Earth?
Relevant Equations
gpe=mgh
I tried just using that equation but I apparently didn't get the correct answer.
 
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The exact expression for GPE, with the zero reference set at infinity, is ##U_{GPE} = -\frac{GMm}{r}##. If we are at the surface of the Earth and consider a small change in ##r##, then ##\delta U = gm \delta r## is approximately correct and we say ##U_{GPE} = mgh##, once we set our zero reference somewhere suitable near the surface of the Earth. This is just an approximation, however.

Since ##424 \text{km}## is quite a long way, you'll need to find ##\Delta U_{GPE}## with the exact expression to get a more reasonable answer!
 
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etotheipi said:
The exact expression for GPE, with the zero reference set at infinity, is ##U_{GPE} = -\frac{GMm}{r}##. If we are at the surface of the Earth and consider a small change in ##r##, then ##\delta U = gm \delta r## is approximately correct and we say ##U_{GPE} = mgh##, once we set our zero reference somewhere suitable near the surface of the Earth. This is just an approximation, however.

Since ##424 \text{km}## is quite a long way, you'll need to find ##\Delta U_{GPE}## with the exact expression to get a more reasonable answer!
So with that equation I got an answer of -8.71*10^15. Does that sound right to you? I'm supposed to answer with 3 sig figs and units.
 
Try and also show your work, otherwise it's not obvious what calculation you've performed :wink:

You're after a change in GPE from radius of ##R_{E}## to ##R_{E} + 424 \text{km}##. So first of all, this is going to be a positive number.

The expression is ##U_{grav} = -\frac{GM_{E}m}{r}##, so you should be able to substitute in the two values of ##r## and subtract to get your change. Or better yet, do it algebraically and substitute in at the end!
 
high schoolphysics said:
So with that equation I got an answer of -8.71*10^15. Does that sound right to you? I'm supposed to answer with 3 sig figs and units.
The GPE equation above give the value relative to a point an infinite distance from the source of gravity ( where GPE is considered zero). What you want is the difference in GPE between two points.
 
so what are the units??
Also just use mgh first as sanity check...it should be within 7%(424/6000) of exact answer (not quite 3 sig fig!). Then do the exact using 1/r
 
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