Flow of liquid through a hole and distance traveled

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SUMMARY

The discussion focuses on calculating the distance a liquid stream travels when flowing from a 10mm hole in a storage tank filled with liquid at a height of 5m and a density of 490 kg/m³. The flow rate is given as 0.207 kg/s, leading to a calculated velocity of 5.45 m/s. The stream is determined to travel for 0.7824 seconds, resulting in a horizontal distance of 4.26 meters. The conclusion indicates that the stream will not be contained by a 1m high dike located 1m away from the hole due to the height and velocity of the stream.

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  • Understanding of fluid dynamics principles, specifically the equation Q = pAV.
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jcy128
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Homework Statement


if the flow rate of a liquid from a 10mm hole in a storage tank holding 5m of a liquid with a density of 490 kg/s, is 0.207 kg/s how far will this stream travel before it hits the ground and will it be contained by a dike 1 m away that is 1 m high

Homework Equations



Q=pAV => Q/pA = V
s=ut+1/2at^2
v=d/t

The Attempt at a Solution


so using the eqn Q/pA = V i get a resultant velocity of 5.45 m/s
using the vectors for the horizontal and vertical distances and the eqn s=ut+1/2at^2 I found that with this velocity the stream will travel for 0.7824s
and then using the eqn v=d/t and changing it to find distnace vt= d i found that the stream would travel 4.26m

I am uncertain how to calculate how to determine if the dike will contain the flow, I believe it won't due to the height of the hole and the mass flow rate and velocity of the stream
 
Last edited:
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Welcome to PF!

Hi jcy128! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Your method is correct, but I don't get 5.45 for v, and you seem to have used 3m instead of 5m for t.

For the last part of the question, simply find how long it takes to fall to the level of the top of the dyke, and then see how far it has moved horizontally. :smile:
 

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