Flow Through Orifice Homework: Bernoulli's & Motion Eqs

  • Thread starter Thread starter samjohnny
  • Start date Start date
  • Tags Tags
    Flow Orifice
Click For Summary
SUMMARY

The discussion focuses on solving a homework problem related to fluid dynamics, specifically applying Bernoulli's principle and equations of motion. The participant successfully utilized the equations v = u + at, s = ut + ½ at², and v² = u² + 2as to analyze the flow through an orifice. They determined that the maximum distance x occurs when the hole is drilled at a depth of H/2 below the surface, confirming the solution with the assistance of forum members.

PREREQUISITES
  • Understanding of Bernoulli's principle
  • Familiarity with equations of motion
  • Knowledge of quadratic equations
  • Basic calculus for optimization
NEXT STEPS
  • Study the application of Bernoulli's equation in fluid dynamics
  • Learn how to derive and solve quadratic equations
  • Explore optimization techniques in calculus
  • Investigate practical applications of orifice flow in engineering
USEFUL FOR

Students in physics or engineering courses, educators teaching fluid dynamics, and anyone interested in applying mathematical principles to real-world fluid flow problems.

samjohnny
Messages
83
Reaction score
1

Homework Statement



Please see attached.

Homework Equations


[/B]
img00094.gif

v = u + at
s = ut + ½ at²
v² = u² + 2as

The Attempt at a Solution



I've managed to get the first part of the question applying Bernoulli's principle and then the equations of motion above by considering separately the vertical and horizontal.

As for the second part, I'm not sure how to go about it. I believe that I would simply need to plug what's known into a certain formula and then solve for h; I expect that would yield a quadratic equation with two solutions for h. But I'm not sure what I need to be using to get this?
 

Attachments

  • Flow-through-orifice.JPG
    Flow-through-orifice.JPG
    35.4 KB · Views: 430
Physics news on Phys.org
You already have a quadratic equation for h if you fix x.
 
Suppose you get a distance x if you drill the hole at h=h1. What distance do you get if you drill the hole at h=H-h1?

Chet
 
Thank you for the replies! I've managed to work through and get the answer; it was so simple but I just couldn't see it. For the last part of the question though I'm not too sure how to proceed. Essentially I'm trying to maximise the distance x, but I'm not sure how to do that. I'm assuming I could either differentiate an equation for x and set it to zero and solve, or make an assumption to maximise x. However I'm not sure on an equation to use, or an appropriate assumption to make.
 
You already have an equation for x as a function of the relevant variable. I suggest you do what you just suggested.
 
Thanks for the reply. Ok so I got the depth at which the maximum distance occurs as being at a height H/2 below the surface. Is that correct?
 
samjohnny said:
Thanks for the reply. Ok so I got the depth at which the maximum distance occurs as being at a height H/2 below the surface. Is that correct?
Yes.
 
Thanks a lot for both of your kind help!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
4K
Replies
4
Views
2K
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 19 ·
Replies
19
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
Replies
2
Views
2K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K