How Do You Calculate Fluid Force on a Rotated Square Tank?

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SUMMARY

The discussion focuses on calculating the fluid force on a rotated square tank containing oil. The tank has a height and width of 12 feet and is filled with oil that has a weight-density of 57 lb/ft³. To express the fluid force when the oil is 4 feet deep, the formula f = pA is utilized, where pressure (p) and area (A) are functions that need to be defined. The setup of the definite integral for this calculation is the primary concern of the participants.

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A metal oil tank has cross-section that is a square rotated 45 degrees as shown in the figure above. Its height is 12 ft and width is 12 feet. The oil in the tank has a weight-density of 57 lb/ft3.
Write a definite integral that expresses the fluid force on the end of the tank when the oil is 4 feet deep?

Here is a link to the photo :
http://img17.imageshack.us/img17/2294/76984288.jpg

hopefully you can make it out.

I am not sure how to set up the definite integral.
 
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Well, I think you can figure out out that
f = pA
Right?

Area is a function that you have. Pressure is a function as well. What are these functions?
 

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