Fluid mechanics of a sinking ball

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SUMMARY

The discussion focuses on calculating the volume of water displaced by a sinking ball in a cylindrical container. The correct formula for the volume displaced per unit time is established as πr²V, where r is the radius of the ball and V is the constant sinking speed. A misconception was presented that the volume should be 2πr²V, which was clarified through a geometric interpretation of the ball's path through the water. The explanation emphasizes the cylindrical shape of the displaced volume, confirming the accuracy of the πr²V formula.

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A cylinder is full of water, a ball is sinking vertically along the central height the cylinder (ie the centre of the ball is along the central axis of the cylinder) with a constant speed V ,if the radius of the ball is r and the radius of the cylinder is R (r<R), find the volume of water displaced by the ball per unit time

the answer is "Volume displaced per unit time = pi*r^2*V''(area of a circle*V)
whereas I think it should be 2*pi*r^2*V ("area of a semi-spherical*V)

How to imagine this correctly?

Thanks very much for any hints!
 
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In one second, the ball travels a distance of V. Think of the “envelop” of the path of the ball through water. If we exclude the initial volume of the ball, then it is a cylinder with a concave hemisphere at the starting end and a convex hemisphere at the other end. The area of cross section of the cylinder is πr². If you cut the convex hemisphere and put it in the concave hollow in the starting end, then it becomes a cylinder with length V and area πr². This is the volume displaced per second.
 

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