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Fluid Mechanics question,velocity potential

  1. Aug 15, 2007 #1
    I am new in this place, am studying civil engineering in Spain,Madrid, and is something I do not understand in a theoretical exposition of the velocity/force potential.

    They suppose that the external force that it acts in each point of the fluid and the speed, derive from scalar , so they admit a potential :

    [tex]\frac{\vec{F}}{m}= - \vec{\nabla} U[/tex]

    [tex]\vec{V}= \vec{\nabla} \Omega[/tex]

    If the acceleration depends on the coordinates of the point and the time [tex]\vec{a} ( u',v',w') = f(x,y,z,t)[/tex] :

    [tex]u'= \frac{du}{dt}= \frac{\partial u}{\partial x} \frac{\partial x}{\partial t} +\frac{\partial u}{\partial y } \frac{\partial y}{\partial t} + \frac{\partial u}{\partial z}\frac{\partial z}{\partial t} + \frac{\partial u}{\partial t}[/tex] and thus with the other coordinates of the acceleration

    And here my doubt comes, I do not understand as they obtain to this expression:

    [tex]u'= \frac{\partial^2 \Omega}{\partial x^2} \frac{\partial \Omega}{\partial x} +\frac{\partial^2 \Omega}{\partial x \partial y} \frac{\partial \Omega}{\partial y} + \frac{\partial^2 \Omega}{\partial x \partial z}\frac{\partial \Omega}{\partial z} + \frac{\partial^2 \Omega}{\partial x \partial t}[/tex]

    if somebody can help to understand it me, would be thanked for. Thank you very much
  2. jcsd
  3. Aug 15, 2007 #2


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    Dearly Missed

    First of all, don't use partials where they don't belong!

    Now, we have
    Thus, we may write the expression for the acceleration in the x-direction, i.e, u' as:

    Now, insert:

    See if you get it right now!
  4. Aug 15, 2007 #3
    Compound functions always was my nightmare

    [tex]\frac{\partial}{\partial t} \left(\frac{\partial \Omega}{\partial x}\right)=\frac{\partial}{\partial x} \left(\frac{\partial \Omega}{\partial x}\right) \underbrace{\frac{dx}{dt}}_{u}+\frac{\partial}{\partial y} \left(\frac{\partial \Omega}{\partial x}\right) \underbrace{\frac{dy}{dt}}_{v} + \frac{\partial}{\partial z} \left(\frac{\partial \Omega}{\partial x}\right) \underbrace{ \frac{dz}{dt}}_{w}+ \frac{\partial}{\partial t} \left(\frac{\partial \Omega}{\partial x}\right) \frac{dt}{dt}[/tex]

    that is what it did not see, thank you very much to solve the doubt to me
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