Fluid Shear Paradox: Is There Shear?

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Discussion Overview

The discussion revolves around the concept of shear in a fluid exhibiting forced vortex flow with constant angular velocity. Participants explore whether shear exists in such a scenario, considering the implications of Newton's shearing theory and the perspective of fluid particles versus external observers. The conversation includes theoretical considerations and speculative reasoning about the nature of strain in rotating fluids.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Exploratory

Main Points Raised

  • Some participants argue that the differential linear velocity in a rotating fluid is only observable by an external observer, leading to questions about the existence of shear from the perspective of fluid particles.
  • Others propose that the rate of deformation tensor is frame invariant and request a velocity distribution to further the discussion.
  • A participant draws an analogy with a boat on a lake, questioning whether strain occurs in the water due to differential linear velocity in a rotating frame.
  • One participant speculates that the derivative of (r w) with respect to r (where w is angular velocity) may not yield meaningful strain, suggesting that there is no tangential strain in a rotating rod either.
  • Another participant asserts that in the case of rigid body rotation, there is no deformation occurring, emphasizing the need to separate rigid body rotations from rates of deformation to understand stress in fluids.

Areas of Agreement / Disagreement

Participants express differing views on the existence of shear in the described fluid scenario. While some suggest that there is no shear due to rigid body rotation, others challenge this perspective, indicating that the discussion remains unresolved with multiple competing viewpoints.

Contextual Notes

The discussion involves assumptions about the nature of fluid motion and the definitions of shear and strain, which may not be universally agreed upon. The implications of frame invariance and the interpretation of the rate of deformation tensor are also points of contention.

vin300
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A fluid with forced vortex flow and constant angular velocity is given. Newton's shearing says there must be strain due to differential linear velocity. The problem is, the difference of linear velocity is only visible to the external observer, the fluid particles themselves do not observe relative difference, thus accounting to only centrifuging and nothing else. So is there shear or not?
 
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vin300 said:
A fluid with forced vortex flow and constant angular velocity is given. Newton's shearing says there must be strain due to differential linear velocity. The problem is, the difference of linear velocity is only visible to the external observer, the fluid particles themselves do not observe relative difference, thus accounting to only centrifuging and nothing else. So is there shear or not?
The rate of deformation tensor is frame invariant. Please provide the velocity distribution, and we can discuss further.

Chet
 
vin300 said:
A fluid with forced vortex flow and constant angular velocity is given. Newton's shearing says there must be strain due to differential linear velocity. The problem is, the difference of linear velocity is only visible to the external observer, the fluid particles themselves do not observe relative difference, thus accounting to only centrifuging and nothing else. So is there shear or not?
If you are on a boat, floating on a lake, and spin around, the water also has differential linear velocity in your rotating frame. Is there strain in the water because of this?
 
Chestermiller said:
The rate of deformation tensor is frame invariant. Please provide the velocity distribution, and we can discuss further.

Chet
. There is nothing extraordinary to provide. I am taking the simplest case of bounded fluid like in a bucket (not a boat in the unending sea), which anybody can imagine to rotate in a similar fashion as a moment arm, and every particle rotates around the same axis making constant angular advances at constant times, with linear variation of linear velocity. I can imagine even though it is frankly speculation, that derivative of (r w) with respect to r would not provide any meaningful "strain" (w is ang. vel.)because there is no tangential strain in a rotating rod either. Clearly there has to be a differential of "angular velocity" in this case for fluid particles to be rubbing past each other and causing distortions.
 
vin300 said:
. There is nothing extraordinary to provide. I am taking the simplest case of bounded fluid like in a bucket (not a boat in the unending sea), which anybody can imagine to rotate in a similar fashion as a moment arm, and every particle rotates around the same axis making constant angular advances at constant times, with linear variation of linear velocity. I can imagine even though it is frankly speculation, that derivative of (r w) with respect to r would not provide any meaningful "strain" (w is ang. vel.)because there is no tangential strain in a rotating rod either. Clearly there has to be a differential of "angular velocity" in this case for fluid particles to be rubbing past each other and causing distortions.
Yes, you are correct. The fluid is rotating as a rigid body here, and there is no deformation occurring. To get rates of deformation in a fluid, we need to subtract out the rigid body rotations of the fluid elements. We do this by resolving the velocity gradient tensor into an antisymmetric part (the vorticity tensor, which accounts for rotation) and the symmetric part (the rate of deformation tensor), which accounts for rates of strain. In Newtonian fluid mechanics, it is only the symmetric part of the velocity gradient tensor that determines the stress tensor.

Chet
 

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