Flux across a plane with varying electric field

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SUMMARY

The discussion centers on calculating the electric flux through a plane located at x=3, subjected to a varying electric field defined as E = α y² x i + α z² y j. The flux is computed using the formula Φ = ∮ E · dA, where the differential area vector dA is oriented in the i direction. The final result for the flux through the plane is determined to be (L⁴/3) α x, leading to a specific value of L⁴ α when x is set to 3.

PREREQUISITES
  • Understanding of electric flux and the concept of vector fields.
  • Familiarity with the integral calculus, particularly double integrals.
  • Knowledge of vector notation and operations in physics.
  • Proficiency in applying Gauss's Law in electrostatics.
NEXT STEPS
  • Study the application of Gauss's Law in different geometries.
  • Learn about vector calculus, specifically divergence and curl operations.
  • Explore the implications of varying electric fields in electromagnetic theory.
  • Practice solving problems involving electric flux through various surfaces.
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering majors, and anyone interested in understanding electric fields and their effects on surfaces in electrostatics.

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Homework Statement


I got home from a test, had an extra credit problem semi memorized and am wondering how I was suppose to solve.

http://i.imgur.com/cIOdSvk.png

A plane with sides L is at x=3 . An electric field E = α y^2 x i + α z^2 y j passes through (where \alpha is a constant). Find the flux through the plane. (Givens are L, \alpha

Homework Equations



\Phi = \oint E \cdot dA

The Attempt at a Solution



Frankly I didn't feel like I knew what I was doing. The plane varies along y and z and the vector for dA will always go in the i direction

dA i = dydz i
E \cdot dA = \alpha y^2 x dydz
\int_0^L \int_0^L y^2 x dydz
L \alpha x \frac{y^3}{3}|^L_0
\frac{L^4}{3} \alpha x

x=3

L^4 \alpha
 
Last edited:
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Your work looks correct to me.
 

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