Flywheel with weight - Rotational Inertia

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SUMMARY

The discussion focuses on calculating the kinetic energy of a system involving a flywheel and a hanging weight. The flywheel has a mass of 15 kg and a radius of 0.25 m, while the weight is 4.7 kg. The user correctly calculated the angular velocity as 4.4 rad/s but encountered issues with the kinetic energy calculation, arriving at 7.381 J, which is incorrect. The equations used include K(rotational) = 0.5Iw^2, I = 0.5m(wheel)r^2, and KE = 0.5m(block)v^2.

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Hey everyone! I have a small problem with part b. I am wondering if i miscalculated something. Any ideas? Thanks!


Homework Statement



A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 4.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.


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a) When the 4.7 kg weight is dropping with a speed of 1.1 m/s, what is the angular velocity of the flywheel?
w = rad/s *
4.4 OK


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b) When the 4.7 kg weight is moving with a speed of 1.1 m/s, what is the kinetic energy of the entire system? This one seems really easy, but for some reason I keep getting the wrong answer.

Homework Equations



K(rotational) = 0.5Iw^2
I = 0.5m(wheel)r^2
KE = 0.5m(block)v^2


The Attempt at a Solution



KE(system) = 0.5[0.5m(wheel)r^2]w^2 + 0.5m(block)v^2

0.5*[0.5*15*0.25^2]*(4.4^2) + 0.5*4.7*(1.1^2)
KE(system) = 4.5375 + 2.8435 = 7.381 J


For some reason 7.381 is not correct.
 
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