Fnet>10.5What causes the block to not initially move up or down the incline?

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Homework Help Overview

The problem involves a block resting on an inclined plane connected to a hanging bucket of water via a pulley. The scenario examines the forces acting on the block to determine why it does not initially move up or down the incline, considering factors such as mass, friction, and gravitational components.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the net forces acting on the block, including gravitational components, tension from the bucket, and friction. There are attempts to clarify the relationship between these forces and the conditions for static friction. Some participants question the calculations and assumptions regarding static friction and net force.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved. Some guidance has been provided regarding the conditions under which the block would remain stationary, but there is no explicit consensus on the initial conditions or calculations.

Contextual Notes

There is mention of a potential error in the original question from the paper, leading to confusion about whether the block moves or remains stationary. The problem involves specific coefficients of friction and the dynamics of a leaking bucket, which may affect the analysis.

rash92
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Homework Statement


A block of mass 30 kg rests 12 m from the bottom
of an inclined plane that is at an angle of 60 to the horizontal. It is connected by a rope of negligible mass via a frictionless pulley to a bucket of mass 5 kg of water, hanging vertically as shown in Fig. Q3. The static and dynamic coefficients of friction between the block and the plane are 0.7 and 0.4, respectively. Water leaks from the bucket at a constant rate of 20 g s-1.

Show that the block will not initially move up or down the incline

if the above is unclear, it is question 3 b on past paper that is attached.

Homework Equations



sohcahtoa equations
Friction = mu*R
R = mgcos60
F = ma
mu(static max) = .7
mu(dynamic) = .4


The Attempt at a Solution


after doing a free body diagram trying to look at whether the block can go down, i got the net force on the block is:
Fnet = component of gravity - tension from bucket - friction
Fnet = Mblock*gsin60 - Mbucket*gsin60 - Mblock*mu*gcos60
= 30gsin60 - 5gson60 - 5*.7*gcos60
= 121.3 N

the question is saying that there should be no net positive force (since the static friction should go up and cancel it, but using max static friction I'm still getting a net force).
 

Attachments

  • F31C01-E1 Exam.pdf
    F31C01-E1 Exam.pdf
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  • answer attempt 1.png
    answer attempt 1.png
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Last edited:
Physics news on Phys.org
Find the net force of mgsinθ and tension of the bucket.
If this is less than μsmgCosθ then it will not move.
Since no motion net force=static friction
 
Last edited:
the tension is in the opposite direction of mgsinθ though, tension is in the same direction as the friction would be.
 
Friction will oppose any motion.
We need net force to move an object.
For static friction, it is equal to the force apply(object not moving).
If you push lightly on an object on a rough surface and its not moving, the force you apply equal to friction. In this case friction is not equal to μstaticmg but equal to force applied.
When the force apply =μstaticmg then it will start to move. Since the maximum static friction is reached.
http://en.wikipedia.org/wiki/Friction#Static_friction
 
Last edited:
i know that, but it still wasn't working.

EDIT: turns out the question in the paper was wrong, it DOES move.
 
Yes you are right

|30gSin60°-5g|>μ30gCos60°
|21|>10.5
 
Last edited:

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