Fooling around with Hamilton-Jacobi theory: can this be right?

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The discussion centers on the Hamilton-Jacobi theory, specifically addressing the relationship between momentum p and Hamilton's principal function S(x,t). The equation H(x, ∂S/∂x) + ∂S/∂t = 0 is analyzed, revealing that while p is a dynamical variable, ∂S/∂x is dependent on both x and t. The correct interpretation is that p(t) equals ∂S/∂x evaluated at x(t), leading to the definition of a function \hat{p}(x,t) = ∂S/∂x. The original poster acknowledges a misunderstanding but seeks feedback on their explanation.

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A system with one particle in one dimension x, momentum p, and hamiltonin H(x,p). Hamilton's principal function S(x,t) is a function satisfying.

[tex]H(x,\frac{\partial S}{\partial x})+\frac{\partial S}{\partial t}=0[/tex]

Now when we say that

[tex]p=\frac{\partial S}{\partial x}[/tex]

this is somewhat nonsensical. The LHS, p, is a dynamical variable, independent of x, whereas the RHS is a function of x and t. It makes sense to refer to x(t) and p(t) separately, but not generally of p(x,t).


What [tex]p=\frac{\partial S}{\partial x}[/tex] must mean is that along any particular solution (x(t), p(t)) in the flow of solutions in phase space, it is the case that


[tex]p(t)=\frac{\partial S}{\partial x}|_{x=x(t)}[/tex]


That is, we can speak of a function [tex]\hat{p}(x,t)\equiv\frac{\partial S}{\partial x}[/tex] and then it is true that if x(t),p(t) are solutions to the equations of motions then for all t


[tex]p(t)=\hat{p}(x(t),t)[/tex].


Let me pause here before proceeding to the question proper. Is what I say so far correct?
 
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You are correct that partial derivative notation is ambiguous (cf. the additional notation which accompanies thermodynamic identities), although it should not normally cause confusion.
 
Thanks, confinement.

Actually, I don't need to post the actual question now. I figured out where I was going wrong. However, I would be interested in any comments about the OP.
 

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