vane12
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In a practice, a football players runs the pattern shown above. Leg A is 3.0 meters long, leg B is 13.0 meters long and leg C is 23.0 meters long. The angle φ between legs B and C is 38.0°. (Legs A and B are perpendicular.)
1.)What is x component of her displacement? (Assume the x direction to be horizontal on that drawing above.)
(A+B+C)x =
2.)What is y component of her displacement? (Assume the y direction to be vertical on that drawing above.)
(A+B+C)y =
For to find the x and y component I did the following:
Ax=3cos0°=3
Bx=13cos38°=10.24
Cx=23cos(-38°)=18.12
Ay=3sin90°=3
By=13sin38°=8.00
Cy=23sin(-38°)=-14.16
(A+B+C)x=31.336 which I got correct but for (A+B+C)y=-3.16 which I didn't get correct and I don't know what I did wrong??
1.)What is x component of her displacement? (Assume the x direction to be horizontal on that drawing above.)
(A+B+C)x =
2.)What is y component of her displacement? (Assume the y direction to be vertical on that drawing above.)
(A+B+C)y =
For to find the x and y component I did the following:
Ax=3cos0°=3
Bx=13cos38°=10.24
Cx=23cos(-38°)=18.12
Ay=3sin90°=3
By=13sin38°=8.00
Cy=23sin(-38°)=-14.16
(A+B+C)x=31.336 which I got correct but for (A+B+C)y=-3.16 which I didn't get correct and I don't know what I did wrong??