Football Pattern Vectors Question

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The discussion revolves around calculating the x and y components of a football player's displacement based on the lengths of three legs and the angle between two of them. The player runs with leg A at 3.0 meters, leg B at 13.0 meters, and leg C at 23.0 meters, with a 38° angle between legs B and C. The calculations for the x component were confirmed correct at 31.336, but the y component was incorrectly calculated as -3.16. Participants highlighted confusion regarding the perpendicularity of legs A and B, given the angle between them, and suggested that the calculations for Ay may need reevaluation. Clarifications on the use of trigonometric functions and the importance of illustrations were also emphasized.
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In a practice, a football players runs the pattern shown above. Leg A is 3.0 meters long, leg B is 13.0 meters long and leg C is 23.0 meters long. The angle φ between legs B and C is 38.0°. (Legs A and B are perpendicular.)

1.)What is x component of her displacement? (Assume the x direction to be horizontal on that drawing above.)
(A+B+C)x =
2.)What is y component of her displacement? (Assume the y direction to be vertical on that drawing above.)
(A+B+C)y =

For to find the x and y component I did the following:

Ax=3cos0°=3
Bx=13cos38°=10.24
Cx=23cos(-38°)=18.12

Ay=3sin90°=3
By=13sin38°=8.00
Cy=23sin(-38°)=-14.16


(A+B+C)x=31.336 which I got correct but for (A+B+C)y=-3.16 which I didn't get correct and I don't know what I did wrong??
 
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Welcome to PF.
I'm a bit confused how leg A and B are perpendicular but there is only a 38 deg angle difference between the two. For Ay you have 3sin90 but for Ax you have 3cos0?
Seems that your Ay is incorrect since you got part 1.
In the future illustrations go a long way.
 
Here is a picture.
 

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By = 0
 
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