Football Player Kicking Ball: Find Clearance of Uprights

  • Thread starter Thread starter hackett5
  • Start date Start date
  • Tags Tags
    Ball
Click For Summary
SUMMARY

The discussion focuses on calculating the clearance of a football kicked by a player at a speed of 20 m/s and an angle of 53 degrees, aimed at uprights 36 meters away and 3.05 meters high. The horizontal range formula, Range = vi² sin(2Θ) / g, indicates the ball travels 39.23 meters, while the height formula, Height = vi² sin²(Θ) / (2g), shows a maximum height of 13.02 meters. To determine if the ball clears the uprights, participants suggest calculating the time it takes to reach 36 meters and substituting that time into the height equation.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of trigonometric functions in physics
  • Basic grasp of gravitational acceleration (g = 9.81 m/s²)
NEXT STEPS
  • Calculate the time of flight to reach 36 meters using the horizontal motion equations
  • Apply the height formula to find the ball's height at 36 meters
  • Explore variations in angle and speed to analyze different kicking scenarios
  • Study the effects of air resistance on projectile motion
USEFUL FOR

This discussion is beneficial for physics students, sports scientists, and coaches interested in understanding projectile motion and optimizing kicking techniques in football.

hackett5
Messages
9
Reaction score
0

Homework Statement



A football player has to kick a ball through the uprights that are 36m away and 3.05 high. He kicks the ball at 20m/s and at an angle of 53 degrees. By how much does the ball clear or fall short of the goal?

Homework Equations


Horizontal Range= vi2 sin 2[tex]\Theta[/tex]/ g

Height = vi2sin2[tex]\Theta[/tex]/2g

The Attempt at a Solution



Using the formulas for range and hieght, I found that the ball traveled a total of 39.23m and reached a maximum height of 13.02. The ball traveled far enough, but how do I find how high the ball was at 36m to see if there was enough height?
 
Physics news on Phys.org
Hint: calculate the time at which the ball was at 36 m, and then plug that time into the equation that determines the height of the ball.
 

Similar threads

  • · Replies 39 ·
2
Replies
39
Views
5K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K