For a linear mapping F, how do I define F^2?

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The discussion centers on the properties of a linear mapping F where it is defined that F = F^2. This condition indicates that F is a projection operator. Consequently, for any vector v, the relationship F(v) = F(F(v)) holds true, confirming that the dimension, kernel, and image of F remain unchanged when considering F^2. Thus, F retains its characteristics as a projection in linear algebra.

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Hi. This is a homework question, so I can't ask or give out too much info.

SO, there is a linear mapping F, and it is given that F=F^2.

Can I assume that everything about F, i.e. dimension, kernel, image, etc, is exactly the same for F^2? Or does it just mean that given a vector v, F(v) = F(F(v))?

Thank you
 
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stgermaine said:
Hi. This is a homework question, so I can't ask or give out too much info.

SO, there is a linear mapping F, and it is given that F=F^2.

Can I assume that everything about F, i.e. dimension, kernel, image, etc, is exactly the same for F^2? Or does it just mean that given a vector v, F(v) = F(F(v))?

Thank you

It means F(v)=F(F(v)).
 
hi stgermaine! :smile:

if F = F2, F is called a projection

think how an "ordinary" projection, say from 3D to a plane or a line, works :wink:
 
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