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For which value of x horizontal Tangent Line

  • Thread starter chaosblack
  • Start date
16
0
For which value of x....horizontal Tangent Line

1. Homework Statement

For which value of x does f(x) = [tex]\frac{k}{ax^{2}+bx+c}[/tex] have a horizontal tangent line?


2. Homework Equations

Quotient Rule?

F'(x) = [g(x)a'(x) - a(x)g'(x)]/g(x)^2?


3. The Attempt at a Solution

Am I supposed to just sub it into a quotient rule format, making the derivative equal to 0?

So it would look like

0 = 0 - (2ax + b)/[[ax[tex]^{2}[/tex]+bx+c][tex]^{2}[/tex]]? (and then simplify of course?)
 
Last edited:

Answers and Replies

Shooting Star
Homework Helper
1,975
4
That's correct. But there are certain restrictions on the values of a, b, and c.

(Also, when there is only a constant in the numerator, like f(x) = k/g(x), then you can directly use f'(x) = k d/dx[1/(g(x)] = k[-g'(x)/[g(x)^2], which is nothing but the quotient rule in a lesser number of steps.)
 
16
0
okay thanks, so the answer would just be the derivative set equal to 0?
 
308
0
yes it is
 
16
0
okay thanks alot
 

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