For which value of x horizontal Tangent Line

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Homework Help Overview

The discussion revolves around determining the value of x for which the function f(x) = k/(ax² + bx + c) has a horizontal tangent line, focusing on the application of derivatives and the quotient rule.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the quotient rule for finding the derivative and whether setting the derivative equal to zero is the correct approach to identify horizontal tangents.

Discussion Status

Some participants confirm the approach of setting the derivative to zero, while others mention restrictions on the coefficients a, b, and c, indicating that there are additional considerations in the problem.

Contextual Notes

There are hints at specific conditions regarding the values of a, b, and c that may affect the solution, but these details are not fully explored in the discussion.

chaosblack
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For which value of x...horizontal Tangent Line

Homework Statement



For which value of x does f(x) = [tex]\frac{k}{ax^{2}+bx+c}[/tex] have a horizontal tangent line?


Homework Equations



Quotient Rule?

F'(x) = [g(x)a'(x) - a(x)g'(x)]/g(x)^2?


The Attempt at a Solution



Am I supposed to just sub it into a quotient rule format, making the derivative equal to 0?

So it would look like

0 = 0 - (2ax + b)/[[ax[tex]^{2}[/tex]+bx+c][tex]^{2}[/tex]]? (and then simplify of course?)
 
Last edited:
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That's correct. But there are certain restrictions on the values of a, b, and c.

(Also, when there is only a constant in the numerator, like f(x) = k/g(x), then you can directly use f'(x) = k d/dx[1/(g(x)] = k[-g'(x)/[g(x)^2], which is nothing but the quotient rule in a lesser number of steps.)
 
okay thanks, so the answer would just be the derivative set equal to 0?
 
yes it is
 
okay thanks a lot
 

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