Force applied to lawnmower and resulting acceleration

[NewJersey]

A 25-kg lawnmover is pushed with a force of 3oN directed 37degrees downward fron the horizontal?

a) The acceleration of the lawnmover is
b) The upward force exerted by the lawn is

Fx= 30 cos(37)= 23.96N
Fy= 30 sin(37)= 18N

a= 23.96N
25kg = .96m/s^2

b= W=25* 9.87= 245

W+Fy= 245+18= 263

Is this right?

Homework Equations

The Attempt at a Solution

 

[einstein_a_go_go]

looks OK to me (is g=9.87 a typo?)