Force applied to lawnmower and resulting acceleration

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SUMMARY

The discussion centers on calculating the acceleration and upward force exerted by a 25-kg lawnmower pushed with a force of 30N at a 37-degree angle downward from the horizontal. The horizontal component of the force is calculated as 23.96N, resulting in an acceleration of 0.96 m/s². The weight of the lawnmower is determined to be 245N, and the total upward force exerted by the lawn is 263N when combined with the vertical component of the applied force.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic trigonometry for force component calculations
  • Knowledge of gravitational force calculations (g=9.87 m/s²)
  • Familiarity with free body diagrams
NEXT STEPS
  • Review Newton's Second Law of Motion applications
  • Study trigonometric functions in physics contexts
  • Explore free body diagram techniques for force analysis
  • Investigate the effects of angle on force components
USEFUL FOR

Physics students, educators, and anyone involved in mechanics or force analysis will benefit from this discussion.

NewJersey
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A 25-kg lawnmover is pushed with a force of 3oN directed 37degrees downward fron the horizontal?

a) The acceleration of the lawnmover is
b) The upward force exerted by the lawn is

Fx= 30 cos(37)= 23.96N
Fy= 30 sin(37)= 18N

a= 23.96N
25kg = .96m/s^2

b= W=25* 9.87= 245

W+Fy= 245+18= 263

Is this right?



Homework Equations





The Attempt at a Solution

 
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looks OK to me (is g=9.87 a typo?)
 

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