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Force applied to lawnmower and resulting acceleration

  1. Nov 16, 2007 #1
    A 25-kg lawnmover is pushed with a force of 3oN directed 37degrees downward fron the horizontal?

    a) The acceleration of the lawnmover is
    b) The upward force exerted by the lawn is

    Fx= 30 cos(37)= 23.96N
    Fy= 30 sin(37)= 18N

    a= 23.96N
    25kg = .96m/s^2

    b= W=25* 9.87= 245

    W+Fy= 245+18= 263

    Is this right?

    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Nov 17, 2007 #2
    looks OK to me (is g=9.87 a typo?)
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