Force applied to simple hand pump and resulting PSI

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SUMMARY

The discussion focuses on calculating the air pressure generated by a simple hand pump, akin to a bicycle pump, when a force is applied to its handle. The key formula established is that pressure (PSI) is derived from the force exerted divided by the cross-sectional area of the piston. Additionally, the impact of friction between the O-ring and the inner wall of the pump is acknowledged, although the primary calculation can be simplified for rough estimates. Understanding these principles allows for better predictions of pump performance.

PREREQUISITES
  • Basic understanding of pressure calculations (Pressure = Force/Area)
  • Familiarity with the mechanics of hand pumps
  • Knowledge of friction and its effects on mechanical systems
  • Concept of cross-sectional area in cylindrical objects
NEXT STEPS
  • Research the effects of friction on pneumatic systems
  • Learn about the mechanics of bicycle pumps and their design
  • Explore advanced pressure calculation methods for varying conditions
  • Investigate materials used for O-rings and their impact on performance
USEFUL FOR

Engineers, mechanics, and hobbyists interested in fluid dynamics, pneumatic systems, and the design of hand-operated pumps.

fred_1985
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I hope I am asking this in the right forum.

Lets say you have a simple hand pump, similar to a bicycle pump, and you exert X amount of force on the handle. How do you calculate the resulting air pressure it creates out of the small valve at the end?

Obviously friction between the O-ring and inner wall of the pump is going to come into play, but a rough estimate would do.

Thanks.
 
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Pressure is force divided by area. Force on the handle, cross sectional area of the piston.
 

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