Force between conducting spheres

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 8K views
dekonig
Messages
2
Reaction score
0
X and Y are two identical conducting spheres separated by a distance d. X has a charge of +6µC and Y has a charge of -2µC. The electric force between them is +F (i.e. attractive). The spheres are touched together and are then returned to their original separation d. What is the new value of the force between them?

Any help is greatly appreciated. I assumed that since the net charge should remain the same after, there would be no change in the value of the force, but the answer scheme gives the answer as -F/3.
 
Last edited:
Physics news on Phys.org
thanks for the reply man, i think i got it. The charges become +2µC on both sphere X and Y, at which point it's just subbing the before and after values for the charge into F=(kq1q2)/r2, and since, they're now like charged, the force becomes a repulsive one, hence -F/3