Equilibrium Force: Solving for Centre of Mass | Homework Statement

  • Thread starter Thread starter CH Lee
  • Start date Start date
  • Tags Tags
    Equilibrium Force
Click For Summary
SUMMARY

The discussion centers on solving for the center of mass in a static equilibrium scenario involving a pole and a box. The relevant equation derived is (1 + tan Θ)/(1 - tan Θ), which relates to the forces acting on the system. Participants emphasize the importance of both translational and rotational equilibrium, represented by the equations ΣF = 0 and Στ = 0. The consensus is that person A will carry more weight due to their higher position in the setup.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with the equations of motion, specifically F = ma
  • Knowledge of torque and its relation to rotational equilibrium
  • Basic trigonometry, particularly the tangent function
NEXT STEPS
  • Study the conditions for static equilibrium in detail
  • Explore the concept of torque and its calculations in various scenarios
  • Learn about the center of mass and its implications in physics problems
  • Investigate real-world applications of static equilibrium in engineering
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone interested in understanding the principles of static equilibrium and center of mass calculations.

CH Lee
Messages
2
Reaction score
0

Homework Statement



Untitled.png

Homework Equations

The Attempt at a Solution


I'm not sure about which topic it is asked. I think it's something about the centre of mass . Because the statement " The pole and the box do not change form" . The answer is
(1 + tan Θ)/(1 - tan Θ)
 
Physics news on Phys.org
What are (all!) the relevant equations for static equilibrium ?

Who do you think will have to carry more in the right picture ? B or A ? Why ?

The "don't change form" remark is to reassure you the center of gravity stays in the same place in the box/pole combo.
 
BvU said:
What are (all!) the relevant equations for static equilibrium ?

Who do you think will have to carry more in the right picture ? B or A ? Why ?

The "don't change form" remark is to reassure you the center of gravity stays in the same place in the box/pole combo.

A will carry more, I think it's because he's in higher position.
And is there any special formula for static equilibrium ? I just draw a triangle and use the formula F=ma.
 
Hehe, you never had to carry something heavy down the stairs, I suppose ?

The conditions for equilibrium I hinted at in post #1 are in the first place ##\Sigma \vec F = 0## So that with your formula a = 0 ##\Rightarrow## v = constant. v = 0 remains v = 0. No translation.

But that's not enough. You also want no rotation, in other words: ##\Sigma \vec \tau = 0##.
And now the positions where the forces act come in the expressions.
 
Last edited:
CH Lee said:
A will carry more, I think it's because he's in higher position.
And is there any special formula for static equilibrium ? I just draw a triangle and use the formula F=ma.

F = ma comes into question when acceleration comes into question. Here, a = 0 and v = 0. All forces balance each other out. FA and FB act vertically upward. In which direction do you think 'W' acts?
 
The forces are vertical. That is a constraint on the answer given by the question statement. In an actual case of carrying a couch down a ramp the people doing the carrying probably would not arrange their hand-holds that way, but the problem requires it.

The pole is not rotating while it is being carried.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
16
Views
2K
Replies
4
Views
2K