Force in The X direction using Lever Arm

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SUMMARY

The discussion focuses on calculating the force required to move a 500 lb car using a 12-inch lever arm attached to the wheel axle. The user attempts to sum the moments about the axle, resulting in the equation (3*500) - 12(Fx), where Fx is calculated to be 125 lbs. This value is questioned by the user, indicating a need for further clarification on the mechanics involved in the lever system.

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drummer8807
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Homework Statement



What is the Force Needed in the X direction?

I have a 500 lb Car and attached to the Wheel axle is a 12 inch long lever arm going straight down. The pivot point is at the axle and a cylinder is pushing the arm at the end of it. What force do I need to push this 500 pound car 3 inches forward?

Homework Equations





The Attempt at a Solution


Do I sum the moments about that axle at which I would get (3*500)-12(Fx) where Fx=125lbs...that number seems high...
 
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welcome to pf!

hi drummer8807! welcome to pf! :smile:
drummer8807 said:
What is the Force Needed in the X direction?

I have a 500 lb Car and attached to the Wheel axle is a 12 inch long lever arm going straight down. The pivot point is at the axle and a cylinder is pushing the arm at the end of it. What force do I need to push this 500 pound car 3 inches forward?

i don't understand the question :confused: …

horizontally, an insect could push it (slowly!)
 
How much force if I push on that lever arm do I need to move it 3 inches is what I am suppose to find out...
 

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