What is the Force Needed in the X direction?
I have a 500 lb Car and attached to the Wheel axle is a 12 inch long lever arm going straight down. The pivot point is at the axle and a cylinder is pushing the arm at the end of it. What force do I need to push this 500 pound car 3 inches forward?
The Attempt at a Solution
Do I sum the moments about that axle at which I would get (3*500)-12(Fx) where Fx=125lbs...that number seems high...