In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The system has a small piston with a cross-sectional area of 0.057m^2 and a large piston with a cross-sectional area of 0.208m^2. An engine weighing 2900N rests on the large piston. What force must be applied to the small piston to lift the engine? If the engine rises 0.235m, how far does the smaller piston move? I correctly found the force to be 794.712N. I thought that the smaller piston moves the same length as the engine rising, but I could be wrong. I don't know how to figure that out.