Water flows at a speed of 0.75 m / s through a U-shaped tube whose cross-section is circular with a radius of 10 mm. How large is the force F to be to compensate for water power on the tube?
I am not sure. Perhaps;
Conservation of momentum
Density = mass/volume
The Attempt at a Solution
I believe that the speed of water flow is the same through the whole pipe but the velocities have different signs in each side of the pipe. Of course the mass is constant.if I use conservation of momentum I will have:
Fdt=2mv. The mass is not given but if we knew the volume we could find it as m=ρV. And how can I separate F from Fdt?
I tried this(wrong);
Fdt=2mv=2m(dx/dt) --->F=2m(d^2x/dt^2)=2ma=0 since velocity is constant.