- #1

azurken

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## Homework Statement

Two charges are placed between the plates of a parallel plate capacitor.

One charge is q1 and the other is q2 = 5.00 microC. The charge per unit

area on each of the plates has a magnitude of σ = 1.30 x 10^-4 C/m^2. The

magnitude of the force on q1 due to q2 equals the magnitude of the force

on q1 due to the electric field of the parallel plate capacitor. What is the

distance r between the two charges?

q2=5.00 x 10^-6

σ = 1.30 x 10^-4

r?

## Homework Equations

E=σ/E0

E=F

F=8.99x10^9 x (q1 x q2)/r^2

E0=8.852x10^-12

## The Attempt at a Solution

The only thing I don't know what to do with this one is the q1. I'm sure I'm using the right formulas but I can't figure out what to do with the q1.

I'm assuming my final answer will be something like r = sqrt((k x q1 x q2)/E)

The E which I can get from dividing the sigma by the E0 which should be 14685946.68

The final answer should be 5.53 cm but I honestly do not know how to get there because I don't know how to solve for q1.