Force of Gravity in a 2 Dimensional Universe

In summary, the conversation discusses the possibility of a hypothetical two-dimensional universe and whether gravity could exist in such a world. It is suggested that in a 2D universe, the Newtonian potential would be logarithmic, and using polar coordinates, it can be shown that the gravitational field of a point charge would be -GM/r, which differs from the 3D gravitational field by a power. It also mentions the possibility of stable orbits and the presence of conic sections in this universe. A link to a more detailed discussion on this topic is provided.
  • #1
starfish99
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0
I know that Edwin Abbott more than 100 years ago wrote about a hypothetical universe with only two dimensions. I wonder if the force of gravity could exist in such a universe(please no general relativity). How would the force of 2 masses vary with distance? Could there be stable orbits and would they be part of conic sections even though cones do not exist in this universe(circle, ellipse,parabola, hyperbola)? Would there be an analogue in the 2D universe to Kepler's Laws in our universe?
 
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  • #2
For a 2 dimensional world, the Newtonian potential would be logarithmic as opposed to ##1/r##. To see this, consider a localized point charge in this 2 dimensional space; Poisson's equation in the vacuum region of the point mass will just be ##\nabla^{2}\varphi = 0##. The isotropy of this system in the 2 dimensional space implies that ##\varphi = \varphi(r)##, where we are using polar coordinates. Evaluating the Laplacian in polar coordinates, we then find that ##\frac{\mathrm{d} }{\mathrm{d} r}(r\frac{\mathrm{d} \varphi}{\mathrm{d} r}) = 0## i.e. ##r\frac{\mathrm{d} \varphi}{\mathrm{d} r} = \alpha = \text{const.}## so ##\frac{\mathrm{d} \varphi}{\mathrm{d} r} = \frac{\alpha}{r}## implying ##\varphi = \alpha \ln r + \beta##. The additive constant is arbitrary and can be set to zero. The multiplicative constant can be found using Gauss's Law and comes out to ##\alpha = GM## giving us ##\varphi = GM \ln r ##. Hence the gravitational field of the point charge in the 2 dimensional space is ##g = -\nabla\varphi = -\frac{GM}{r}\hat{r}##, which differs by a power from the gravitational field of a point mass in 3 dimensional space.For more details and for a discussion of Keplerian trajectories as well as stable orbits in a 2 dimensional world, see: http://www.dwc.knaw.nl/DL/publications/PU00012213.pdf
 
  • #3
Thanks WannabeNewton
 

What is force of gravity?

Force of gravity is the force that attracts objects with mass towards each other. It is a fundamental force in the universe and is responsible for keeping planets in orbit around the sun.

How is force of gravity calculated in a 2 dimensional universe?

In a 2 dimensional universe, force of gravity is calculated using the formula F = (G*m1*m2)/r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

What factors affect the force of gravity in a 2 dimensional universe?

The force of gravity in a 2 dimensional universe is affected by the masses of the two objects and the distance between them. The force increases as the masses increase and decreases as the distance between the objects increases.

Can force of gravity be negative in a 2 dimensional universe?

No, force of gravity cannot be negative in a 2 dimensional universe. It is always a positive value, as it is an attractive force between two objects.

How does the force of gravity change with the change in distance between two objects in a 2 dimensional universe?

The force of gravity is inversely proportional to the square of the distance between two objects in a 2 dimensional universe. This means that as the distance between the objects increases, the force of gravity decreases and vice versa.

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