Force of nail after being struck by a hammer

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SUMMARY

The discussion centers on calculating the force exerted on a nail by a hammerhead weighing 5 pounds, traveling at 5.4 ft/s and stopping in 0.00081 seconds. The initial momentum (Pi) is calculated as 0.84375 lb·ft/s, derived from the equation P=mv, where mass is determined as 5/32 lb. The force (F) is then computed using the formula F=(Pf-Pi)/ΔT, resulting in a force of -1041.67 N, indicating the direction of the force applied to the nail.

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Homework Statement


A 5lb hammerhead, traveling at 5.4ft/s strikes a nail and is brought to a stop in .00081s. The acceleration of gravity is 32ft/s^2, What force did the nail receive?



Homework Equations


The equation I have is F=Pf-Pi/delta T. Both Pf and Pi have a arrow above them going to the right.


The Attempt at a Solution


I know I have to find Pf and Pi, and P=mv. With that said would Pf be 0, since it comes to a stop, and Pi be (5lb)(5.4ft/s)? And I am guessing that delta T would .00081s?
 
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unteng10 said:

Homework Statement


A 5lb hammerhead, traveling at 5.4ft/s strikes a nail and is brought to a stop in .00081s. The acceleration of gravity is 32ft/s^2, What force did the nail receive?

Homework Equations


The equation I have is F=Pf-Pi/delta T. Both Pf and Pi have a arrow above them going to the right.

The Attempt at a Solution


I know I have to find Pf and Pi, and P=mv. With that said would Pf be 0, since it comes to a stop, and Pi be (5lb)(5.4ft/s)? And I am guessing that delta T would .00081s?

Welcome to PF.

The real question here is what is the mass of the hammerhead? Since they give you acceleration of 32ft/s2, then this suggests to me this is how much it weighs. So I would say you need to determine your mass as 5/32 and then multiply by your 5.4 to get your momentum and then proceed as you were apparently intending.
 
LowlyPion said:
Welcome to PF.

The real question here is what is the mass of the hammerhead? Since they give you acceleration of 32ft/s2, then this suggests to me this is how much it weighs. So I would say you need to determine your mass as 5/32 and then multiply by your 5.4 to get your momentum and then proceed as you were apparently intending.

So, p=mv which would be p=(5/32)(5.4) which equals .84375.
Then, F=Pf-Pi/delta T, which would be (0)-(.84375)/(.00081)-(0), which would equal -1041.67 N, but you can't have a negative force can you? Am I doing this right, or am I missing something?
 
unteng10 said:
So, p=mv which would be p=(5/32)(5.4) which equals .84375.
Then, F=Pf-Pi/delta T, which would be (0)-(.84375)/(.00081)-(0), which would equal -1041.67 N, but you can't have a negative force can you? Am I doing this right, or am I missing something?

Which direction did you choose as + ?
And what is the question asking?
What force did the nail receive?
So if the impact of the hammer resulted in a (-) force to the hammer that sounds like it received an upward force and the nail received a downward force.
 

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