Force on 1 point charge in a 4 point charge system

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SUMMARY

The discussion focuses on calculating the total force exerted on one charge in a system of four identical charges positioned at the corners of a square with side length L. The forces acting on the charge are derived from Coulomb's law, specifically F=k(q1q2/r^2). The diagonal force component introduces the factor of L√2, which is essential for resolving the forces correctly. The final expression for the resultant force on the charge is F=resultant = kQ^2(1+2√2)/(2L^2).

PREREQUISITES
  • Coulomb's Law (F=k(q1q2/r^2))
  • Vector resolution of forces
  • Understanding of geometric relationships in a square
  • Basic trigonometry (specifically 45-degree angles)
NEXT STEPS
  • Study vector resolution techniques in physics
  • Learn about the implications of Coulomb's Law in multi-charge systems
  • Explore the Pythagorean theorem applications in force calculations
  • Investigate the concept of electric field strength and its relation to point charges
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Students and educators in physics, particularly those studying electrostatics and force interactions in multi-charge systems.

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Homework Statement



Four identical charges are placed at the corners of a square of side side L.
Find the magnitude total force exerted on one charge by the other three charges.
Express your answer in terms of the variables Q, L and appropriate constants.

where did the L root2 in the solution come from?


Homework Equations



F=k(q1q2/r^2)





The Attempt at a Solution



let the charge Q at bottom left corner be considered, it is ready to move under repulsion

f1 = F(top, bottom) = kQ^2/L^2 [south] = x
f2=F(right, bottom) = kQ^2/L^2 [west] = x
f3 = F(diagonal, bottom) = kQ^2/[L root2]^2 [south-west]
f3 = x/2
--------------------------------------…
resolve f3 along south & west

F(net south) = x + [x/2] cos 45 = x[1+ 1/2root2]
F(net south) = x[1+2root2] /2root2 = F
F(net west) = x[1+2root2] /2root2 =F

F(resultant) = sqrt[F^2 + F^2] = F root2
F(resultant) = [ x[1+2root2] /2root2 ][root2]
F(resultant) = x[1+2root2] /2
F(resultant) = kQ^2[1+2root2] /2L^2
 
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Use Pythagoras theorem to find the diagonal of the cube.
 

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