Force on a current carrying wire

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Homework Help Overview

The discussion revolves around a current-carrying wire bent into a semicircle within a uniform magnetic field. The original poster seeks to demonstrate that the magnetic force acting on the closed wire loop is zero, while also exploring practical applications of the principle of force on a current-carrying conductor in a magnetic field.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss whether the problem can be approached mathematically or geometrically. There are inquiries about how to calculate the magnetic force on the wire and whether the force on the semicircular segment is indeed zero.

Discussion Status

Some participants have offered hints regarding the integration of forces over the semicircular segment and the straight segment. There is an ongoing exploration of the reasoning behind the assumption that the net force is zero, with no explicit consensus reached.

Contextual Notes

The original poster notes that the question is not part of a homework assignment but relates to an upcoming experiment. There is mention of a closed loop without an apparent battery source, which may influence the discussion on the forces involved.

vorcil
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a)
A current‐carrying wire bent into a semicircle of radius r forms a close circuit as shown in the figure. A uniform magnetic field is directed normal to the linear section and in the plane of the loop. Show that the magnetic force acting on the closed wire loop is zero.
http://upload.wikimedia.org/wikipedia/commons/e/e9/Semicircle.svg

b)
List three items which operate on the principle “force acting on a current‐carrying conductor in a magnetic field”.

- n.b these aren't homework questions, I'm doing an experiment tomorrow and this was in a book I'm reading (related to the experiment)

I'm not sure how to solve the first one, can I do this mathematically? or is it more of a geometrical problem?

b - not sure if I know any practical applications of force on a current carrying wire,
All i can think of is the magneto in microwaves
anyone know any?
 
Last edited by a moderator:
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vorcil said:
b - not sure if I know any practical applications of force on a current carrying wire,
All i can think of is the magneto in microwaves
anyone know any?

I can think of two applications that are in your computer. You can probably hear one of them, and you listen to the other every day.
 
vorcil said:
I'm not sure how to solve the first one, can I do this mathematically? or is it more of a geometrical problem?
How do you find the magnetic force on a current-carrying wire?
 
Doc Al said:
How do you find the magnetic force on a current-carrying wire?

Use the lorentz force law,

Fmag = Q*(v*b)

then use the right hand rule, it says the magnetic field is into the semi circle, perpendicular to it's normal

not really sure how to solve it from here
 
vorcil said:
Use the lorentz force law,

Fmag = Q*(v*b)
When dealing with a current, use:
[tex]\vec{F} = \vec{I}\ell \times \vec{B}[/tex]
 
vorcil said:
how do i show that the magnetic force is 0 in the semicircle
What makes you think that the force on the semicircle is zero?

What's the force on the straight segment?

Hint: Find the force on an element of the semicircle, then integrate over the entire segment.
 
Doc Al said:
What makes you think that the force on the semicircle is zero?

What's the force on the straight segment?

Hint: Find the force on an element of the semicircle, then integrate over the entire segment.

http://img529.imageshack.us/img529/6398/questionk.jpg

that's why i think it's 0, the question basically says it

-

would i get the circumference

(2*pi*r)/2 + (2r) = the length
= pi*r + 2r = total length of wire,

it's a closed loop with no apparent battery source
 
Last edited by a moderator:
  • #10
vorcil said:
that's why i think it's 0, the question basically says it
There are two segments: the semicircular segment and the straight segment. The net force on the entire closed loop is zero. To show that, compute the force on each segment.
 

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