Force on a Negative Charge Q1 in the Presence of a Long Rod

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SUMMARY

The discussion centers on calculating the forces acting on a negative charge Q1 in the presence of a long, negatively charged rod with total charge Q0. For a stationary charge Q1, the force is determined using Coulomb's Law, yielding F = k(Q_e)^2/(D^2). When Q1 moves out of the page at speed v1, the total force is zero due to the angle of interaction being 90 degrees. The implications of motion direction on the force experienced by Q1 are also explored, particularly when moving leftward.

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  • Coulomb's Law for electrostatic force calculations
  • Understanding of electric fields generated by linear charge distributions
  • Basic principles of motion in physics
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jaded18
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Consider a very, very long rod (length L) with total negative charge Q0,
uniformly spread out. The rod is located in the plane of the page, is parallel to the top of the
page, and moves right‐ward with a speed v. There is a negative charge Q1 located a small
distance D away from the rod. Neglect gravity.

a) What is the total force (magnitude and direction) acting on the charge Q1 if it is NOT
moving?
b) What is the total force (magnitude and direction) acting on the charge Q1 if it is moving
with out of the page at speed v1?
c) What is the total force (magnitude and direction) acting on the charge Q1 if it is moving
left‐ward at speed v1?

attempt at ANS:
a) coulomb's law = F = k(QQ)/(r^2) = k(Q_e)^2/(D^2)
b) 0 because angle=90?
c) ...

I need help.
 
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