Force on an Incline Plane Problem HELP

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Homework Help Overview

The problem involves a 63-kg person skiing down a hill inclined at 30° with a coefficient of friction of 0.20, seeking to determine the magnitude of acceleration. The context includes the application of Newton's laws and frictional forces.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of normal force and net force, with one participant expressing confusion about the sign of the acceleration. Others suggest reviewing the equations used and the implications of substituting values.

Discussion Status

Some participants have provided calculations and alternative formulations of the equations involved. There is an ongoing exploration of the relationships between forces, with no explicit consensus reached on the correct approach or final answer.

Contextual Notes

Participants are navigating the implications of using absolute values for acceleration and the cancellation of mass in the equations. There is a focus on ensuring the correct application of trigonometric functions in the context of the incline.

whoopie88
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Homework Statement


A 63-kg person on skis is going down a hill sloped at 30° from the horizontal. The coefficient of friction between the skis and the snow is 0.20. What would be the magnitude of the acceleration?

Homework Equations


f=ma
fg=mg
fnet=mAnet
Ff=μῦFn

The Attempt at a Solution


I got -102.14, but I'm supposed to put it in as 102.14 right? Because the magnitude is the absolute value of whatever I get..? I found Fnet by subtracting Ff from Fg,x. I got 535.23 for Fn.

PLEASE HELP!? I put in 102.14 on the Webassign but it came back as wrong.

Thank you all!
 
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Show your calculations.
 
Fn = Fg,y
Fn = mgcos30
Fn = 63(9.81)cos30
Fn = 535.23

Fnet = mgsin30 - μῦFn
mAnet = mgsin30 - μῦFn
Anet = gsin30 - μῦFn
Anet = 9.81sin30 - 0.2(535.23)
Anet = -102.14

And as I mentioned earlier, I changed it to positive 102.14.

Thanks for your time.
 
mAnet = mgsin30 - μῦFn

The above equation should be

m*Anet = m*g*sin(30) - μ*m*g*cos(30)

Now solve for A.
 
Thank you for your help, I didn't realize m canceled out for the Fn formula until you showed me how I could use substitution. Thank you!
 

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