- #1

jj8890

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## Homework Statement

You drag a suitcase of mass 9.2 kg with a force of F at an angle 52.1 degrees with respect to the horizontal along a surface with kinetic coeﬃcient of friction 0.54. The acceleration of gravity is 9.8 m/s^2.

If the suitcase is moving with constant velocity 1.65 m/s, what is F ?

## Homework Equations

F=ma

## The Attempt at a Solution

F=ma

a = 0

FcosΘ - Friction = (9.2)(0)

F - µR = 0

F - (0.54)((9.2)(9.8)-mgsinΘ)) = 0

F- (0.54)(90.16 - 9.2(9.8)sin52.1) = 0

F - 0.54(19.016) = 0

F = 10.268 N

but this is not right..I think that I am doing something wrong...Any help would be great. Thanks