Force on Blocks: Fig. 5-1a & b, Mass 30 kg, Forces 28 & 14 N

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The discussion focuses on the dynamics of two blocks on a smooth surface under the influence of a constant horizontal force, Fa. In Fig. 5-1a, block A exerts a force of 28.0 N on block B, while in Fig. 5-1b, block A exerts a force of 14.0 N on block B. The total mass of the blocks is 30.0 kg. The acceleration of the blocks can be calculated using Newton's second law, F=ma, leading to an acceleration of 0.933 m/s² when 28.0 N is applied to block B.

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Fig. 5-1a shows two blocks on a smooth surface. A constant horizontal force Fa is applied to block A, which pushes against block B with a 28.0 N force horizontally to the right. In Fig. 5-1b, the same force Fa is applied to block B so that block A pushes on block B with a 14.0 N force horizontally to the left. The blocks have a total mass of 30.0 kg.

W0074-N.jpg


Fig. 5-1

(a) What is the magnitude of the acceleration of the blocks in Fig. 5-1a?

what i tried was F=ma so 28=30a so 28/30=a

(b) What is the magnitude of the force Fa?
 
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B-80 said:
(a) What is the magnitude of the acceleration of the blocks in Fig. 5-1a?

what i tried was F=ma so 28=30a so 28/30=a
28.0 N is the force on block B (in case a), not on both blocks. You have to use all the information given to solve this. Hint: The same force pushes the same total mass in each case.
 

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