Force on conductor in magnetic field

[Suyash Singh]

Homework Statement

Homework Equations

Emf=B l V V is (velocity)
F=QVB

The Attempt at a Solution

Emf=BLV
Work=QBLV
Force=BLV
how come V=Q/m. its not possible or is it?

 

[kuruman]

This is not a Faraday's law question. You need to calculate the impulse F dt given to the conductor and set it equal to its momentum change.

 

[Suyash Singh]

This is not a Faraday's law question. You need to calculate the impulse F dt given to the conductor and set it equal to its momentum change.

mv=integral(fdt)

but why is force in my book given as b l i (i is current)

 

[Suyash Singh]

This is not a Faraday's law question. You need to calculate the impulse F dt given to the conductor and set it equal to its momentum change.

and the force i was giving before is it the force on each charged particle?

 

[kuruman]

but why is force in my book given as b l i (i is current)

Because a segment of wire of length $\vec L$ carrying current $I$ in a magnetic field $\vec B$ experiences a force $\vec F=I\vec L \times \vec B$.
You don't need an integral for the impulse. Assume that the force is constant while it lasts in which case the impulse is J = F Δt.

 

[Suyash Singh]

Because a segment of wire of length $\vec L$ carrying current $I$ in a magnetic field $\vec B$ experiences a force $\vec F=I\vec L \times \vec B$.
You don't need an integral for the impulse. Assume that the force is constant while it lasts in which case the impulse is J = F Δt.

ohhhh ok. i already knew that formula it was written differently so i couldn't recognise it.
thankyou.
mv = ILBsin(90 degree) Δt (force x time change)
=ILBΔt

now since Ixt=Q
v=QLB/m :)

 

[kuruman]

That's it.