Force on Moving Charges in a Magnetic Field

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SUMMARY

The discussion centers on calculating the magnetic force on a positive charge \( q \) moving in the xy-plane with a velocity vector defined as \( \hat{v} = v\cos(\theta)\hat{x} + v\sin(\theta)\hat{y} \) in the presence of a magnetic field directed along the +z axis. The magnetic force can be determined using the Lorentz force equation, which involves the cross product of the velocity vector and the magnetic field vector. The resulting force direction can be expressed as a linear combination of the unit vectors \( \hat{x} \), \( \hat{y} \), and \( \hat{z} \) based on the angle \( \theta \).

PREREQUISITES
  • Understanding of the Lorentz force equation.
  • Familiarity with vector cross products.
  • Knowledge of unit vectors in three-dimensional space.
  • Basic principles of electromagnetism.
NEXT STEPS
  • Study the application of the Lorentz force equation in various scenarios.
  • Learn how to compute vector cross products in detail.
  • Explore the implications of magnetic fields on moving charges.
  • Investigate the behavior of charged particles in uniform magnetic fields.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the dynamics of charged particles in magnetic fields.

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Homework Statement


Consider the example of a positive charge q moving in the xy plane with velocity [tex]\hat{v}[/tex] = vcos([tex]\theta[/tex])[tex]\hat{x}[/tex] + vsin([tex]\theta[/tex])[tex]\hat{y}[/tex] (i.e., with magnitude v at angle [tex]\theta[/tex] with respect to the x-axis). If the local magnetic field is in the +z direction, what is the direction of the magnetic force acting on the particle?
Express the direction of the force in terms of [tex]\theta[/tex], as a linear combination of unit vectors, [tex]\hat{x}[/tex], [tex]\hat{y}[/tex], [tex]\hat{z}[/tex].


Homework Equations


Cross product.
[tex]\vec{C}[/tex] = [tex]\vec{A}[/tex] X [tex]\vec{B}[/tex] = (AxBy - AyBx)[tex]\hat{z}[/tex] + (AyBz - AzBy)[tex]\hat{x}[/tex] + (AzBx - AxBz)[tex]\hat{y}[/tex]


The Attempt at a Solution


I don't know what to plug in, and overall am just confused as to what the formula means.

Any explanation would be greatly appreciated!
 
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You only need to to apply the equation for the Lorentz force here. What have you learned about how to evaluate the cross product of two vectors?
 

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