ownsail Messages 5 Reaction score 0 Thread starter Feb 22, 2006 #1 If two springs, having different spring constants, are in a series (lined up, NOT parrallel): is the Force pulling the spring = (sum of spring constants)*(distance stretched) ?
If two springs, having different spring constants, are in a series (lined up, NOT parrallel): is the Force pulling the spring = (sum of spring constants)*(distance stretched) ?
phucnv87 Messages 66 Reaction score 0 Feb 22, 2006 #2 No, no. If the force apply to the [tex]1^{st}[/tex] spring, the equation will be [tex]F=k_1\Delta l_1[/tex][/color]
No, no. If the force apply to the [tex]1^{st}[/tex] spring, the equation will be [tex]F=k_1\Delta l_1[/tex][/color]
ownsail Messages 5 Reaction score 0 Feb 22, 2006 #4 in other words, if F = kx: F=(k1)(x1) and F=(k2)(x2) but not F=(k1+k2)(x1+x2)
phucnv87 Messages 66 Reaction score 0 Feb 22, 2006 #5 That's right, and the equivalent constant is [tex]\frac{1}{k}=\frac{1}{k_1}+\frac{1}{k_2}+...+\frac{1}{k_n}[/tex][/color]
That's right, and the equivalent constant is [tex]\frac{1}{k}=\frac{1}{k_1}+\frac{1}{k_2}+...+\frac{1}{k_n}[/tex][/color]