Force on Series of Springs: Does It Equal Sum?

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If two springs, having different spring constants, are in a series (lined up, NOT parrallel): is the Force pulling the spring = (sum of spring constants)*(distance stretched) ?
 
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No, no. If the force apply to the [tex]1^{st}[/tex] spring, the equation will be

[tex]F=k_1\Delta l_1[/tex][/color]
 
in other words, if F = kx:
F=(k1)(x1)
and
F=(k2)(x2)

but not F=(k1+k2)(x1+x2)
 
That's right, and the equivalent constant is

[tex]\frac{1}{k}=\frac{1}{k_1}+\frac{1}{k_2}+...+\frac{1}{k_n}[/tex][/color]