Force on three Bolts holding up a Jet Engine

Click For Summary
The discussion centers on calculating the force on three bolts supporting a 1400-kg jet engine. The initial assumption was that the force on the bolts would be 0 Newtons since they are not moving, which is incorrect. The correct interpretation involves calculating the tension on each bolt, as they support the weight of the engine. Each bolt would therefore bear a load of approximately 4,600 Newtons when the plane is stationary. Understanding the distinction between net force and tension is crucial for solving this problem accurately.
mopit_011
Messages
17
Reaction score
8
Homework Statement
A 1400-kg jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load. Calculate the force on each bolt as the plane waits in line for clearance to take off.
Relevant Equations
F=ma
y=y0+v0t+(at^2/2)
My solution was that there would be a force of 0 Newtons on the bolt as the bolt is not moving. But this answer is wrong. Where am I going wrong?
 
Physics news on Phys.org
mopit_011 said:
Homework Statement:: A 1400-kg jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load. Calculate the force on each bolt as the plane waits in line for clearance to take off.
Relevant Equations:: F=ma
y=y0+v0t+(at^2/2)

My solution was that there would be a force of 0 Newtons on the bolt as the bolt is not moving. But this answer is wrong. Where am I going wrong?
I doubt they mean to ask for the net force, though I agree that is a strictly correct interpretation. Rather, they want the tension on each bolt.
 
haruspex said:
I doubt they mean to ask for the net force, though I agree that is a strictly correct interpretation. Rather, they want the tension on each bolt.
Ohhhh ok. Thank you so much!
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

Replies
13
Views
961
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
1
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
4
Views
4K
  • · Replies 36 ·
2
Replies
36
Views
3K
  • · Replies 29 ·
Replies
29
Views
5K
  • · Replies 9 ·
Replies
9
Views
2K