- #1

09jml90

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## Homework Statement

Two blocks m

_{1}= 9.4 kg and m

_{2}= 4.9 kg are connected by a homogeneous rope that has a mass of m

_{r}= 1.42 kg. A constant vertical force, F = 184.9 N, is applied to the upper block.

What is the magnitude of the acceleration of the system?

What is the magnitude of the tension in the rope at the bottom end of the rope?

What is the magnitude of the tension in the rope at the top end of the rope?

## Homework Equations

Newton's Second Law = [tex]\sum F[/tex] = ma

## The Attempt at a Solution

For the first part, I took the objects to be part of one system, used F=ma with 184.9=F, combined the 3 masses, and solved for a. I then subtracted 9.8 m/s^2 to get 1.96 m/s^2.

Tension Parts: I wasn't really sure how to do this from the get go, so I started trying some things. I'm also still not 100% sure about the relationships going on here. For the mag. of the tension of the rope at the bottom end of the rope, I took (4.9kg)(11.76 m/s^2) + (4.9kg)(9.8 m/s^2). I also tried it adding the mass of the rope on to the second block, so (5.62kg)(9.8m/s^2) + (9.4kg)(11.76 m/s^2)- I then wasn't sure if I needed to take into account block 1.

Because I couldn't figure out the bottom tension, I didn't attempt to do the tension of the top of the rope.

Any help would be appreciated. Thank you