(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A charged particle A exerts a force of 2.67 μN to the right on charged particle B when the particles are 13.9 mm apart. Particle B moves straight away from A to make the distance between them 18.6 mm. What vector force does particle B then exert on A?

2. Relevant equations

F = Ke*|q1||q2|/r^2, Ke=8.99*10^9

3. The attempt at a solution

I assumed that q1 = 2.67 micronewtons, and had an idea that we need to solve for for q2..I think, so I just took the equation and set Ke=|q1||q2|/r^2 and solved for q2. I got 1.34 for an answer..don't know if that is even right..can someone clarify?

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# Homework Help: Force question using Couloumb's law

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