Force reactions of balls in a tube

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SUMMARY

The discussion focuses on calculating the reactions from the walls of a tube containing two smooth balls, each with a radius of 10 cm and a weight of 6 kg. The participants utilize trigonometry to analyze the forces acting on the balls, concluding that the horizontal reactions from the walls amount to 45 N. The conversation also addresses the equilibrium condition of the tube and the implications of the distance between the balls, which is 1.2 cm apart. The participants explore the absence of a normal force between the lower cylinders and seek clarification on previous related questions.

PREREQUISITES
  • Understanding of trigonometry in physics
  • Knowledge of equilibrium conditions in mechanics
  • Familiarity with forces and moments
  • Basic concepts of smooth surfaces and frictionless interactions
NEXT STEPS
  • Study the principles of static equilibrium in mechanics
  • Learn about calculating forces in two-dimensional systems
  • Explore the concept of normal forces in contact mechanics
  • Investigate the effects of distance between objects on force interactions
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their understanding of force interactions in systems with multiple bodies.

Karol
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Homework Statement


Two smooth balls of radius 10[cm] and weight 6[kg] are inside a tube of radius 16[cm] that's on the table. what are the reactions from the walls and what is the minimum mass of the tube to be in equilibrium

Homework Equations


Disassembling of forces using trigonometry

The Attempt at a Solution


The middle triangle is a classic 3-4-5 straight angle triangle multiplied by 15 so the reactions from the walls are 3x15=45. but the reactions are horizontal so at any weight the cylinder stays in place, no?
 

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Aren't the balls exerting a moment on the tube?

Chet
 

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