Force required for cutting sheet metal

Thread starter eng_taha_a
Start date May 9, 2018
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Cutting Force Metal Sheet metal

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SUMMARY

The required force to cut sheet metal using an electrically powered shear machine is calculated based on the ultimate tensile strength (UTS) of the material and the area being sheared. According to Kalpakjian's formula, the peak punch force is determined by the equation 0.7 X UTS X A, where A is the area of the cut. For a sheet thickness of 1.25 mm and a UTS of 350 N/mm², the cutting force is estimated to be around 6000 N, factoring in the blade angle and the area under the blade during the cutting process. The design must account for mechanical advantages and potential deflections to ensure effective cutting.

PREREQUISITES

Understanding of shear force calculations in metal cutting
Familiarity with ultimate tensile strength (UTS) concepts
Knowledge of blade geometry and cutting angles
Experience with mechanical advantage in cutting tools

NEXT STEPS

Research "Shear Force Calculation in Metal Cutting" for detailed methodologies
Study "Ultimate Tensile Strength (UTS) and Its Applications" for material properties
Explore "Mechanical Advantage in Cutting Tools" to optimize design
Read "The Science and Engineering of Cutting" by Tony Atkins for advanced insights

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Mechanical engineers, manufacturing professionals, and anyone involved in the design and operation of cutting tools and machinery will benefit from this discussion.

May 17, 2018

CWatters

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eng_taha_a said:

this dimension is about 100 mm

So at the end of a 1000mm cut I make the blade angle about 5.8 degrees, the length of the cut about 15mm and the triangular area under the blade about 11sq mm.

The eqns linked to by Asymptotic in #2 and jrmichler in #5 are similar and suggest the cutting force is some factor between 0.7 and 1.5 multiplied by UST multiplied by the area, so somewhere between..

0.7*350*11 = 2700N
and
1.5*350*11 = 5800N

Lets call it 6,000N.

eng_taha_a said:

will it be 420,875 N or less or more ?

The force required is considerably less.

The torque required is the force multiplied by the length of the blade so 6000 * 1m = 6000 Newton Meters.

eng_taha_a said:

this is the electric motor vision and ,but not the final decision

I notice that the arm that connects the electric actuator to the blade is shorter than the blade. Let's call the length of the actuator arm "L" (meters). Then the force the actuator would have to produce is: 6000/L Newtons.